in Class A addresses the first bit identifies the class. The next 7 bits identify the network and the rest are the IP's that belong to that network. However these networks are then broken down using subnets . Class A networks are not given to private clients or small private organisations. So if you want to know how many bits are there for identifying hosts in a Class A network, the answer is 32-8 = 24 bits. However if you mean how many bits are reserved for hosts in your private network space, that depends on your subnet and router. Most routers use NAT to allow multiple hosts to use a single external IP address. I hope this answers your question :)
8 bit
0.0.0.0 --> Current network (only valid as source address) 10.x.x.x --> Private address space for class A networks 14.x.x.x --> Public data network 127.0.0.1 --> Loopback (refers to own computer) 128.0.0.x --> Reserved (IANA) 169.254.0.x --> Zeroconf network 172.16.x.x through 172.31.x.x --> Private address space for class B networks 191.255.0.x --> Reserved (IANA) 192.0.0.x --> Reserved (IANA) 192.88.99.0 --> IPv6 to IPv4 relay 192.168.x.x --> Private address space for class C networks 198.18.0.0 --> Benchmark tests 223.255.255.0 --> Reserved (IANA) 224.0.0.x --> Multicasting 240.0.0.x --> Reserved 255.255.255.255 --> Broadcast I think I've got that right.
Any address in the 10.0.0.0 - 10.255.255.255 range is considered a private (reserved) IP address in the class A address space.
The following ranges are reserved for private addresses:Class A: 10.0.0.0 - 10.255.255.255Class B: 172.16.0.0 - 172.31.255.255.Class C: 192.168.0.0 - 192.168.255.255
256
"The RFC 1918 private network numbers are 10.0.0.0, Class Bs between 172.16.0.0 and 172.31.0.0 inclusive, and all Class C networks that begin with 192.168. All addresses that begin with 127 are reserved, but not as valid private IP addresses."
Private IP address ranges:10.0.0.0 to 10.255.255.255172.16.0.0 to 172.31.255.255192.168.0.0 to 192.168.255.255Definitely private =)This is a Class B public address because the first octet ranges from 128 and 191.Sorry! 172.16.50.100 falls in the category of private ip networks.
A class A address is one of the IPv4 class-full networks. There are 3 of these class-full networks in IPv4; class (A, B, and C). The entire IPv4 address range is 32 bits long. The address range is broken up into 4 x (8 bits) referred to as octets, and then giving the whole 32 bit address range. The classes are defined as follows… Class A = reserve the first octet, or 8 bits for network addresses and leave the remaining three for host addresses. Reserving the addresses for the network is also referred to as the network mask. In other words do not assign any address in the reserved, first octet, to a host. Class A = 11111111.00000000.00000000.00000000 also known as a /8 bits reserved for net Class B = 11111111.11111111.00000000.00000000 also known as a /16 bits reserved for net Class C = 11111111.11111111.11111111.00000000 also known as a /24 bits reserved for net So the answer is; a class A network has an 8 bit field for the network, and a 24 bit field for the host
Public network is where the networked computers are not all trusted. Private network is where all computers are trusted. EG. Public network: cyber cafe. EG Private network: Your work or home network.
Its a Class C address.
A class C network supports the most networks - the first three octets or 24 bits gives the largest grouping of networks.
Class C
Nothing (0). Anyone can use a private class A or B address in their network because the packets with those addresses are not routed.