32 bits.
An IPv4 address looks like this:
192.168.1.1
Each number can only go from 0 to 255.
That makes for 256 possible choices for each number.
And 28=256, meaning that there can only be 8 bits per number.
So, 8+8+8+8=32, which means that there are a total of 32 bits in an IPv4 address.
IPv4 is 32 bits wide, or about 4 billion IP addresses; while IPv6 is 128 bits wide, or about 3.4x10^38 IP addresses. The number of addresses between the two has a difference of 79x10^27 times bigger. It is calculated that the world's energy output combined could only support using 1/3rd of the available addresses in this address space.
32 bits wide
The address bus in the 8085 is 16 bits wide.
That depends on the memory architecture of the system.if the memory chips are byte wide and not used to create a multibyte bus, 11 address bits are needed.if the memory chips are 32 bits wide, 9 address bits are needed (with the CPU internally selecting which of the 4 bytes it will use).it the memory chips are 64 bits wide, 8 address bits are needed (with the CPU internally selecting which of the 8 bytes it will use.if the memory chips are 4 bits wide, 12 address bits will be needed and the CPU must perform 2 memory cycles per byte that it needs. (yes, I have seen a computer that worked this way!)etc.
8 Bits Wide
32 bits wide
8 bits.
For the Pentium the front side data bus is 64 bits wide. The back side is 32 bits wide.
The external data bus can be as wide as desired, given the necessary compromises between performance, complexity, and cost. The wider the bus, the faster the theoretical aggregate data transfer rate. In the 8085 and 8088, the external data bus is 8 bits wide; in the 8086, it is 16 bits wide; in the 80386, it is 32 bits wide; and in the modern incarnations of 64 bit processors, it is 64 bits wide.
32 bit
Because that's how Intel designed it. Even though the 8085 is an 8-bit computer, the program counter and stack pointer are 16 bits wide in order to support the address bus, which is also 16 bits wide. In the case of the 8086/8088, the program counter and stack pointer are still 16 bits wide, even though the address bus is 20 bits wide, because the 8086/8088 adds segmentation through the 16 bit segment register which is left shifted by 4.
32 bit