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It depends a little on just how decomposed it is, and whether it's been disturbed or not (native state or excavated and recompacted, or not recompacted), but generally, use of a unit weight of about 135 to 145 pounds per cubic foot or in the range of 3,500 to 4,000 pounds per cubic yard should suffice for estimating purposes.
The pressure 5kPA is about 0.725psi or 104.4lbs/sqft. (we're using feet for the cross section of the straw so that we can use it easily for the height) We know that water has a density of 62.4lbs/ft^2. Therefore, we divide the weight of the water that we can suck up the straw at 5kPa by the density of water. We get the volume of water that we can move. (104.4lbs) / (62.4lbs/ft^3) = 1.67ft^3 Since our column is a 1ft x 1ft column, water will be able to be lifted to 1.67ft.
There is not enough info here to provide an answer. Would need the ambient room conditions along with an accurate load calculation for the room.
You calculate the sqft of the room, a sqft is still a sqft no matter what the tile dimensions are
20 Sqft.
It depends on how many square feet the box will cover. I found two different brands: one covered 22.93 sqft, the other 17.59 sqft. your room is 12' x 14' = 168 sq.ft so 168 sqft / (22.93 sqft / box) = 7.32 boxes for my first example and 168 sqft / (17.59 sqft / box) = 9.55 boxes for my 2nd example Hope this helps
600 sqft/ton so 2 1/2 ton
800 sqft
750,000 gal.
12x12= 144 sqft
You want a about 8000btu for a room that size
7 x 7 = 49
269.23
1418 sqft = 131.74m2