how many bytes are there in a 64-bit machine?
Another Answer:
It takes 8 bytes to store a 64 bit number.
it's 8 bytes of 8 bits in a 64 bit word
how many bytes are there in a 64-bit machine? Another Answer: It takes 8 bytes to store a 64 bit number.
You only need one bit to denote 0 or 1... so 1/8th of a byte would be enough. The actual space taken to store the number 1 would be defined by the type of the variable that is holding the number... if you were programming in C, and used the integer type to store the value 1, it would use 2 bytes - those two bytes, in binary, would read 0000000000000001.
Your question used 50 bytes. This answer used 123 bytes. Your Question was 11 words, this answer is 22 words. Go figure!
That depends what encoding is used. One common (fairly old) encoding is ASCII; that one uses one byte for each character (letter, symbol, space, etc.). Some systems use 2 bytes per character. Many modern systems use Unicode; if the Unicode characters are stored as UTF-16 - a fairly common encoding scheme - many common characters will still use a single byte, while many special symbols (for example, accented characters) will take up two bytes. The number of bits is simply the number of bytes multiplied by 8.
As the 4 byte or nibble is no longer used in computers then the answer is 32 million Bytes to be divided by 4. The answer is a very big number
integrated circuits
bytes are used to represent the amount of capacity in a memory
from <http://docs.oracle.com/cd/B19306_01/server.102/b14220/datatype.htm#i1847> Overview of DATE Datatype The DATE datatype stores point-in-time values (dates and times) in a table. The DATE datatype stores the year (including the century), the month, the day, the hours, the minutes, and the seconds (after midnight). Oracle can store dates in the Julian era, ranging from January 1, 4712 BCE through December 31, 4712 CE (Common Era, or 'AD'). Unless BCE ('BC' in the format mask) is specifically used, CE date entries are the default. Oracle uses its own internal format to store dates. Date data is stored in fixed-length fields of seven bytes each, corresponding to century, year, month, day, hour, minute, and second. The correct answer is 7 bytes for a date column.
Global internet traffic consumes about 607 Tera Bytes every second.Which is 607000000000000 bytes every second. You can say 6.07e+14 is the amount of data in bytes.
4 - one for each character. However, depending on the computer language being used, there is some "overhead" - for example, with "C", the end of a text string is indicated with a null character, so "Bill" would need 5 bytes. Other languages precede strings with their length, the length taking 2, 4 or 8 bytes.
The combination of bits used to represent a particular letter number or character. e.g.: data bytes,
1 petabyte (PB) = 1,000,000,000,000,000 bytes = 1015 bytes. 1 megabyte (MB) = 1,000,000 bytes = 106 bytes. So 1 petabyte = 1,000,000,000 megabytes. A related unit, the pebibyte (PiB) is 1024 terabytes, but this is rarely used, if ever.