m=225 g
Delta T (change in temperature)= 33 C degrees
c (specific heat water liquid)= 1 cal/g(C)
Q=?
Q=mc(delta T)
Q=225g(1 cal/g(C degrees))(33 C degrees)
Q= 7425 calories
I need to find Joules first.
q = mass * specific heat * change in temperature
q = (200 grams)(4.180 J/gC)(85 C - 5 C)
= 66880 Joules
-----------------------now to convert
66880 Joules (1 calorie/4.184 Joules)
= 1.6 X 104 calories
===============
I will have to work in Joules, then convert.
q(Joules) = mass * specific heat * change in temperature
q = (450 grams)(4.180 J/gC)(85.5 C - 80.5 C)
= 9405 Joules
==========
9405 Joules (1 calorie/4.184 Joules)
= 225 calories
------------------
1 calorie is the heat to raise 1 gram of water by 1 deg celsius. You have 200 grams being raised by 80 deg celsius, so the number of calories is 200 x 80 =16,000
200 calories, but we must remember the calories use to measure food are really kilocaloriesor 1000 times greater than a calorie which is the heat energy needed to raise 1 gram 1° Celsius
750 calories assuming no change of state (i.e. solid to liquid or liquid to gas) or 3138 joules
75 degrees
Take the temperature in Fahrenheit subtract 32.Divide by 1.8.The result is degrees Celsius.
Because 40 degrees Celsius is equal to a temperature of 104 degrees Fahrenheit.
323 degrees K When converting from Celsius to Kelvin, you just add the temperature of absolute zero, 273 degrees, to the temperature.
170 degrees Fahrenheit = 76.6 degrees Celsius.
Answer: 15 ºC = 288 K
36.2 degress C to 38 degrees C
135 degrees celsius
20 degrees celsius
350 degrees Fahrenheit is 176.67 degrees Celsius.
6.67 degrees Celsius.
20 degrees Celsius = 68 degrees Fahrenheit.