It takes 1 kcal to raise the temperature of 1 kg of water by 1 degree C. To do this accurately, you need the temperature of the water to determine its density, but for the sake of simplicity, we'll use its value at 4oC, which is 1 g/ml 373 ml is equal to 373g or 0.373kg. Therefore, for that volume of water it should take 0.373 kcal per degree C., so 0.373 x 30 = 11.19 kcal, or 11,190 cal
To calculate the calories needed to heat water, you can use the formula: Q = mcΔT, where Q is the energy in calories, m is the mass of water in grams, c is the specific heat capacity of water (1 calorie/gram °C), and ΔT is the temperature change. First, convert the volume of water to grams and then plug in the values to find the calories required to heat the water by 30°C.
It takes 1 calorie to heat 1 gram of water by 1 degree Celsius. A 2 liter bottle of water weighs around 2000 grams. Therefore, you would need 200,000 calories to heat the water from 0 to 100 degrees Celsius.
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To calculate the total number of calories of heat needed, you can use the formula: Q = m * c * ΔT, where Q is the heat energy in calories, m is the mass of the water, c is the specific heat capacity of water (1 calorie/gram °C), and ΔT is the change in temperature. Assuming you have 100 grams of water, the calculation would be: Q = 100g * 1 cal/g°C * 10°C = 1000 calories.
The heat of vaporization of water is approximately 2260 J/g at a temperature of 100°C. This means that it takes 2260 Joules of energy to convert 1 gram of liquid water into vapor at its boiling point.
The specific heat of water is 4.179 Joules per gram per degree Centigrade. The density of water is 1 gram per cubic centimeter, so one liter is 1000 grams. This means it takes 4179 Joules to raise one liter one degree Centigrade.
It takes 1000 calories to heat 1 litre of water 1 degree C.
It takes 1 calorie to heat 1 gram of water by 1 degree Celsius. A 2 liter bottle of water weighs around 2000 grams. Therefore, you would need 200,000 calories to heat the water from 0 to 100 degrees Celsius.
Nutritionally, none at all. If you are talking about calories as in weight loss and diet, water hasn't got any calories. Thermodynamically, the calorie as a unit of energy is deprecated in favor of the Joule. It takes 1000 calories (or one kilocalorie, also known as one Calorie) to raise the temperature of 1000 g of water one degree C. Because 1 kg of water is approximately one liter, you can get one Calorie (1000 calories) of heat energy per degree C from a liter of hot water as it cools. (Recovering that heat as usable energy is a different matter entirely.)
To raise 1000 grams of water from 50 to 100 degrees requires 50 degrees x 1000 grams of heat, so the answer is 50,000 calories. Water at 100 degrees requires an additional 550 calories to convert 1 gram fully into steam. Therefore the remaining 50,000 calories can convert 50,000/550 grams into steam. So 90.9 grams become steam, and that's the answer.
The heat of vaporization of water is approximately 2260 J/g at a temperature of 100°C. This means that it takes 2260 Joules of energy to convert 1 gram of liquid water into vapor at its boiling point.
200000 calories. 1 gm of water needs 1 cal(calorie) to raise it's temperature through 10C. Now, density of water = 1gm/ml at 40C and we assume that it's density is same at 00C. So we have 2000gm of water. For raising temp by 10C we need 2000 cal. For raising temp by 1000C we need 2000 x 100 cal = 200000 calories
A calorie of energy (NOT to be confused with a Calorie, they are different so watch the caps) is the amount necessary to heat 1 gram of water 1oC, so 30 calories are needed to heat 30 g of water 1 degree. To heat it 70oC would take 2100 calories (or 2.1 Calories) of energy.
To heat one liter of water to 85c you will need a heatproof container that will hold one liter. You will also need Bunsen burner to heat the water and a thermometer to see when itâ??s reached 85c.
First it is important to note the difference between a calorie and a Calorie. By definition a calorie is the amount of heat required to raise the temperature of one gram of water by one degree Celsius at one atmosphere pressure. What we commonly call a Calorie (with a big C) is actually a kilocalorie, or 1000 little calories. Since body temperature is 37.5 degrees Celsius and there are apx 997 grams of water in a liter, we burn about 37,000 calories (37 Calories) for every liter of almost freezing ice water we drink. If we drink the recommended 8 cups/2 liters of water per day, 74 calories isn't much when compared to a 2000 Calorie a day diet, but over a year that adds up to around 27,000 Calories burned!
quantity of heat required =mass*specific heat of water*change in temperature Q=160*1*(77-19)=9280 calories=9.28 kilo calories
1370 calories
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