answersLogoWhite

0


Best Answer

It takes 1 kcal to raise the temperature of 1 kg of water by 1 degree C. To do this accurately, you need the temperature of the water to determine its density, but for the sake of simplicity, we'll use its value at 4oC, which is 1 g/ml 373 ml is equal to 373g or 0.373kg. Therefore, for that volume of water it should take 0.373 kcal per degree C., so 0.373 x 30 = 11.19 kcal, or 11,190 cal

User Avatar

Wiki User

15y ago
This answer is:
User Avatar

Add your answer:

Earn +20 pts
Q: How many calories does it take to heat 0.373 liter of water 30 C?
Write your answer...
Submit
Still have questions?
magnify glass
imp
Related questions

How many calories does it take to heat 1 liter of water 1 degree?

It takes 1000 calories to heat 1 litre of water 1 degree C.


If you have a 2 liter bottle of liquid water at 0 Celsius. About how many Calories are needed to heat up the water to 100 C?

200


How many calories are there in a litre of water?

Nutritionally, none at all. If you are talking about calories as in weight loss and diet, water hasn't got any calories. Thermodynamically, the calorie as a unit of energy is deprecated in favor of the Joule. It takes 1000 calories (or one kilocalorie, also known as one Calorie) to raise the temperature of 1000 g of water one degree C. Because 1 kg of water is approximately one liter, you can get one Calorie (1000 calories) of heat energy per degree C from a liter of hot water as it cools. (Recovering that heat as usable energy is a different matter entirely.)


If you have a liter of water at 50 degrees celsius sea level You heat the water so that you apply 100000 calories About how much of the water will boil Express your answer in grams?

To raise 1000 grams of water from 50 to 100 degrees requires 50 degrees x 1000 grams of heat, so the answer is 50,000 calories. Water at 100 degrees requires an additional 550 calories to convert 1 gram fully into steam. Therefore the remaining 50,000 calories can convert 50,000/550 grams into steam. So 90.9 grams become steam, and that's the answer.


What is the heat of vaporization value of water?

It is approximately 539.4 calories per gram.


How many calories are needed to heat 1 liter of water by 1 degree?

200000 calories. 1 gm of water needs 1 cal(calorie) to raise it's temperature through 10C. Now, density of water = 1gm/ml at 40C and we assume that it's density is same at 00C. So we have 2000gm of water. For raising temp by 10C we need 2000 cal. For raising temp by 1000C we need 2000 x 100 cal = 200000 calories


How much heat is needed to heat 100g of water from 10 to 95 degrees?

A calorie of energy (NOT to be confused with a Calorie, they are different so watch the caps) is the amount necessary to heat 1 gram of water 1oC, so 30 calories are needed to heat 30 g of water 1 degree. To heat it 70oC would take 2100 calories (or 2.1 Calories) of energy.


Which combinations of equipment would be needed to bring one liter of water to 85 degrees celsius?

To heat one liter of water to 85c you will need a heatproof container that will hold one liter. You will also need Bunsen burner to heat the water and a thermometer to see when itâ??s reached 85c.


How many calories do you burn if you drink a cold bottle of water?

First it is important to note the difference between a calorie and a Calorie. By definition a calorie is the amount of heat required to raise the temperature of one gram of water by one degree Celsius at one atmosphere pressure. What we commonly call a Calorie (with a big C) is actually a kilocalorie, or 1000 little calories. Since body temperature is 37.5 degrees Celsius and there are apx 997 grams of water in a liter, we burn about 37,000 calories (37 Calories) for every liter of almost freezing ice water we drink. If we drink the recommended 8 cups/2 liters of water per day, 74 calories isn't much when compared to a 2000 Calorie a day diet, but over a year that adds up to around 27,000 Calories burned!


Kilocalories to heat 160g of water in a kettle from 19 to 77 degrees Celsius?

quantity of heat required =mass*specific heat of water*change in temperature Q=160*1*(77-19)=9280 calories=9.28 kilo calories


How many calories does it take to heat a 100.0 g sample of water from 24.5 degrees to 38.2 degrees?

1370 calories


If it takes 300 calories of heat to change the temperature of water from 10ºC to 70ºC. What is the mass of the water?

cd