There are five digits all together. The number of ways of arranging them is
5 x 4 x 3 x 2 x 1 = 120 .
But the three 2s can be arranged in 3 x 2 = 6 different ways and they all look the same.
And the two 4s can be arranged in 2 different ways and they look the same.
So out of the 120 different ways of arranging all five, there's a group of six
for every possible arrangement of the 2s that all look the same, and there's
a group of two for each possible arrangement of the 4s that both look the
same.
The number of combinations that look different is 120/(6 x 2) = 10 .
And here they are:
2 2 2 4 4
2 2 4 2 4
2 2 4 4 2
2 4 2 2 4
2 4 2 4 2
2 4 4 2 2
4 2 2 2 4
4 2 2 4 2
4 2 4 2 2
4 4 2 2 2
if its not alphanumeric, 999999 variations
120 combinations using each digit once per combination. There are 625 combinations if you can repeat the digits.
Too many to list here-see below.
Just 1.
Any 6 from 51 = 18,009,460 combinations
if its not alphanumeric, 999999 variations
Number of 7 digit combinations out of the 10 one-digit numbers = 120.
216
There are 840 4-digit combinations without repeating any digit in the combinations.
There are 5,040 combinations.
120 combinations using each digit once per combination. There are 625 combinations if you can repeat the digits.
There are 210 4 digit combinations and 5040 different 4 digit codes.
1296 or (6^4)
the answer is = first 2-digit number by using 48= 28,82 and in 3 digit is=282,228,822,822
There are twelve possible solutions using the rule you stated.
Too many to list here-see below.
Too many to list here-see below.