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How many combinations can you get with 9 items but only 5 used at a time?
Wiki User
∙ 15y ago
9C5
= 9!/[(9 - 5)!5!]
= 9!/(4!5!)
= (9 x 8 x 7 x 6 x 5!)/(5! x 4 x 3 x 2 x 1)
= 3 x 7
= 21
Wiki User
∙ 15y ago
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