10 to the third assuming zero is included and can lead, otherwise 9 to the third, ie 729.
This all assumes that you are talking about 3-digit numbers.
* * * * *
No. That may be the number of permutations but those are different from combinations. In a combiation, the order of the digits does not matter so that 123 is the same as 132 or 213 etc.
With repetition, there are 210 COMBINATIONS, including one that is {0,0,0}.
6
0000-9999 (10x10x10x10 or 104) = 10,000 possible combinations allowing for repeated digits. If you are not able to repeat digits then it's 10 x 9 x 8 x 7 or 5,040 possible combinations without repeated digits.
36^36 (36 * 36 * 36 * 36 * 36 *...)
24
10
If the numbers can be repeated and the numbers are 0-9 then there are 1000 different combinations.
If numbers may be repeated . . . 36 If numbers may not be repeated . . . 30 If the sequence doesn't matter . . . 15
9
9999
How many numbers per combination?
If you allow digits to be repeated (for example, 222 or 992), then there are 9 x 9 x 9 = 729 combinations. If you do not allow digits to be repeated, then there are 9 x 8 x 7 = 504 combinations.
The number of combinations of six numbers that can be made from seven numbers will depend on if you can repeat numbers. In all there are over 2,000 different numbers that can be made.
45
9
You did not give us the set to work with...
umm i think there would be 3 combonations. correct this if you think this is wrong. 00, 11, 22,
If the numbers are allowed to repeat, then there are six to the fourth power possible combinations, or 1296. If they are not allowed to repeat then there are only 360 combinations.