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Silicon has a total of 10 core electrons and 4 valence electrons.
I might be wrong but: I know that beryllium has two electrons total and the first ring can only fit two electrons so the number of valance electrons is most likely two. Please correct me if I'm wrong.
Beryllium will lose 2 electrons to satisfy the octet rule (to fill its outer shell).
Beryllium has the electronic configuration 2, 2, so it is likely to lose two electrons, giving it the Helium configuration. However, in practice, beryllium compounds have a high degree of covalent character as the beryllium ion is small and very polarising.
Selenium is Atominc number: 34 It has 6 Valence electrons Therefore you take 6 from 34: 28 core electrons
Beryllium has two valence electrons.
Beryllium has two valence electrons.
Beryllium has two valence electrons.
Beryllium has one valence shell containing two electrons.
2
2,8,18,7... 28 core electrons 7 valence electrons.
Silicon has a total of 10 core electrons and 4 valence electrons.
Oxygen as 2 core electrons and 6 valence electrons.
Boron has 3 valence electrons.Boron has 3 valence electrons.
The valence of beryllium is two.
I might be wrong but: I know that beryllium has two electrons total and the first ring can only fit two electrons so the number of valance electrons is most likely two. Please correct me if I'm wrong.
I am not positive what you mean by "core electrons" but: 57 (total) 7 (valence, outermost) 50 (non-valence, everyone but valence)