Silicon has a total of 10 core electrons and 4 valence electrons.
I might be wrong but: I know that beryllium has two electrons total and the first ring can only fit two electrons so the number of valance electrons is most likely two. Please correct me if I'm wrong.
Beryllium will lose 2 electrons to satisfy the octet rule (to fill its outer shell).
Beryllium has the electronic configuration 2, 2, so it is likely to lose two electrons, giving it the Helium configuration. However, in practice, beryllium compounds have a high degree of covalent character as the beryllium ion is small and very polarising.
Selenium is Atominc number: 34 It has 6 Valence electrons Therefore you take 6 from 34: 28 core electrons
Beryllium has two valence electrons.
Beryllium has two valence electrons.
Beryllium has two valence electrons.
Beryllium has one valence shell containing two electrons.
2
4 electrons, 2 valence electrons
Silicon has a total of 10 core electrons and 4 valence electrons.
Oxygen as 2 core electrons and 6 valence electrons.
The valence of beryllium is two.
I might be wrong but: I know that beryllium has two electrons total and the first ring can only fit two electrons so the number of valance electrons is most likely two. Please correct me if I'm wrong.
In an electrically neutral atom, the number of electrons is the same as the number of protons. Since the number of protons is the atomic number of an atom, and Beryllium has an atomic number of 4, this means that Beryllium has 4 protons in its nucleus. As mentioned previously, if the atom is electrically neutral, then Beryllium will also has 4 electrons.
Bromine (Br) has 35 electrons in total. It has 7 valence electrons (outermost shell) and 28 core electrons (inner electron shells).