There are just 5,005.
Add these together.
If the numbers are allowed to repeat, then there are six to the fourth power possible combinations, or 1296. If they are not allowed to repeat then there are only 360 combinations.
If you are assuming you can repeat any of the numbers then: nx where n=number of options and x= number of spaces using the formula assuming all numbers 0-9 then: 1010 10,000,000,000 is your answer. If numbers can not repeat and have to be used we use the formula: n! Where n is the number of options.Since you want 10 numbers we will do 10! 10! 10*9*8*7*6*5*4*3*2*1 362880 is your answer.
No. Irrational numbers are those that cannot be represented as a fractions. Any number which repeats could be represented as a fraction.
Irrational numbers are numbers that cannot be expressed as fractions with whole numbers. They are generally roots (such as the square root of two) or constants (such as pi and e). They are interesting because they cannot be exactly expressed as decimal numbers because they never terminate or repeat themselves.an irrational number is a number that goes on and on for a long time like pi
imm they would b the same wouldn't they, except number 1 may repeat itself (number 1 and 100-001).
The number of combinations of six numbers that can be made from seven numbers will depend on if you can repeat numbers. In all there are over 2,000 different numbers that can be made.
If you can repeat the numbers within the combination there are 10,000 different combinations. If you cannot repeat the numbers within the combination, there are 5040 different combinations.
9
506 = 15,625 million
If the numbers are allowed to repeat, then there are six to the fourth power possible combinations, or 1296. If they are not allowed to repeat then there are only 360 combinations.
10P4 = 5040
The first digit can be one of five integers (1 to 5) The second - fourth digits one of six integers (0 to 5). So: number of (valid) combinations is 5*6*6*6=1080 * * * * * This gives the number of permutations, not combinations. I am working on the latter.
The rearrangement of 5 figure numbers will be 5x4x3x2x1 which is 120 combinations, when you don't repeat a number.
If they can repeat, then: 17^6=24,137,569 If they can't repeat, then: 17*16*15*14*13*12=8,910,720
Assuming you cannot repeat a single number within the combinations, there are a total of 56 x 55 x 54 x 53 x 52 x 51 = 23377273920 combinations of 56 numbers.
If the 6 digits can be repeated, there are 1296 different combinations. If you cannot repeat digits in the combination there are 360 different combinations. * * * * * No. That is the number of PERMUTATIONS, not COMBINATIONS. If you have 6 different digits, you can make only 15 4-digit combinations from them.
If you are able to repeat numbers you would take 6 * 6 * 6 = 216 combinations. If you are not able to repeat numbers you would take 6 * 5 * 4 = 120 combinations.