2²⁴ = 16 777 216
Over sixteen million
You can represent a maximum of 2^24 colors in RGB. This equals to 16777216 possible colors.
256, 8 bits per pixel = 2^8 colours.
There are 30,240 different 5-digit numbers. Math: 10*9*8*7*6 1st digit has 10 possible choices (0-9) 2nd digit has 9 possible choices (one of the digits was used in the 1st digit) 3rd digit has 8 possible choices 4th digit has 7 possible choices 5th digit has 6 possible choices
One byte For each primary color results in 256 different intensity levels for each primary color. Thus a pixel can take on a color from 256X256X256 or 16.7 milion possible choices. If 1 bit = 256 Color Approximately. Then in 24 bit = 256 X 24 = 6144 color Approximately. Answer is Given By Pranjal Nath From Assam Bsc It(5th Sem) From Kuvempu Univercity. India.
One bit is 2 possible colors, black, 8bit has a possible of 256
1 mega pixel how many pixel
2^10 = 1024 possible colors per each channel (R for example). Then 2^30 for a pixel. This makes 1024^3 = 1073741824 possible different colors for a pixel.
If 'a' is the total number of actions, then the number of possible programs are a2n, 2n internal states and 'a' choices for each state.
Right now there are 12 choices.
You have 2 choices for 20 times, so the number of sequences is 220 or 1048576.
Red Blue Green
As there are 4 numbers and they are all different, they can be arranged in: 4 choices for first number, leaving 3 choices for the second number for each choice of the first, leaving 2 choices for the third number for each of the choices of the first two, leaving 1 choice for the last number for each of the choices for the first three giving: number of choices = 4 x 3 x 2 x 1 = 24 possible orders in total.