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How many different choices of colors are possible if you use 24 bits per pixel?
You can represent a maximum of 2^24 colors in RGB. This equals to 16777216 possible colors.
How many colors are possible if 8 bits pixel is used?
256, 8 bits per pixel = 2^8 colours.
How many 5 digit numbers are there with distinct digits?
There are 30,240 different 5-digit numbers. Math: 10*9*8*7*6 1st digit has 10 possible choices (0-9) 2nd digit has 9 possible choices (one of the digits was used in the 1st digit) 3rd digit has 8 possible choices 4th digit has 7 possible choices 5th digit has 6 possible choices
How many colors are possible if 24 bits per pixel is used?
One byte For each primary color results in 256 different intensity levels for each primary color. Thus a pixel can take on a color from 256X256X256 or 16.7 milion possible choices. If 1 bit = 256 Color Approximately. Then in 24 bit = 256 X 24 = 6144 color Approximately. Answer is Given By Pranjal Nath From Assam Bsc It(5th Sem) From Kuvempu Univercity. India.
How many colors possible if 1 bit pixel is used?
One bit is 2 possible colors, black, 8bit has a possible of 256
What is pixel and Mega Pixel?
1 mega pixel how many pixel
Direct coding of RGB values with 10 bits per primary color how many possible colors do you have for each pixel?
2^10 = 1024 possible colors per each channel (R for example). Then 2^30 for a pixel. This makes 1024^3 = 1073741824 possible different colors for a pixel.
How many different possible agent programs are there in an architecture with n bits of storage?
If 'a' is the total number of actions, then the number of possible programs are a2n, 2n internal states and 'a' choices for each state.
How many different igloo choices are there total on club penguin?
Right now there are 12 choices.
If 20 newborn babies are randomly selected how many different gender sequences are possible?
You have 2 choices for 20 times, so the number of sequences is 220 or 1048576.
How many different colors make up each pixel in a plasma display?
Red Blue Green
How many possible orders are there with these numbers - 3 5 7 and 9?
As there are 4 numbers and they are all different, they can be arranged in: 4 choices for first number, leaving 3 choices for the second number for each choice of the first, leaving 2 choices for the third number for each of the choices of the first two, leaving 1 choice for the last number for each of the choices for the first three giving: number of choices = 4 x 3 x 2 x 1 = 24 possible orders in total.
