An infinity:
1,01+ 1,99+ 8+ 8
1,02+ 1,98+ 8+ 8
or
(-1)+ 1+ 9+ 10
And you can add more decimal spaces and/or negative numbers.
I believe the question was badly asked (I think you meant WHOLE numbers [0,1,2] with non-negative integers).
There are many different combinations of six numbers, but the sum of those numbers would have to be 24.
7
There are many combinations of 2 numbers that sum to 70. Any combination of numbers where the first number is x and the second number is 70-x will sum to 70. For example: 69 and 1 68 and 2 67 and 3 66 and 4...
There are 165 of them and I do not have the patience to list them all.
8
There are many different combinations of six numbers, but the sum of those numbers would have to be 24.
There are 12 different combinations of 3 positive odd numbers that add up to 21. Namely: (There are many permutations of these combinations.) 1,1,9 1,3,17 1,5,15 1,7,13 1,9,11 3,3,15 3,5,13 3,7,11 3,9,9 5,5,11 5,7,9 7,7,7
7
3*5=15 5*3=15 15*1=15
There are many combinations of 2 numbers that sum to 70. Any combination of numbers where the first number is x and the second number is 70-x will sum to 70. For example: 69 and 1 68 and 2 67 and 3 66 and 4...
There are 165 of them and I do not have the patience to list them all.
8
If you have 12 possible numbers with multiple combinations then you should start out with making all the possible combinations; you will find theyre 20. Theyre four numbers out of the twleve that can be divisible by three; 3, 6, 9, and 12. There are 7 combinations where the combinations can equal those four numbers. So the odds of getting a sum divisible by three is 7/20.
There are two ambiguities in this question. First, the numbers 0 through 9 could mean integers or real numbers. If you meant real numbers the answer is infinite, so I presume you mean integers. More to the point, it depends on whether you are only counting combinations of 4 different numbers or allowing duplications (like 4, 4, 5, 5).
110
7 meadowood
Are you asking which two positive integers when added together equal 5285? If so, which of the 2642 different combinations would you prefer? How about 1 & 5284.