I'm going to assume that the sequence of the 5 numbers doesn't matter, because
this sounds to me like another lottery exercise.
Picking 5 numbers out of a bag of 25, there are 25 x 24 x 23 x 22 x 21 / 5 x 4 x 3 x 2 =
53,130 different possible groups of 5.
If the numbers can be repeated and the numbers are 0-9 then there are 1000 different combinations.
9
If numbers may be repeated . . . 36 If numbers may not be repeated . . . 30 If the sequence doesn't matter . . . 15
9
120 WRONG! That is the number of PERMUTATIONS. In the case of combinations, the order of the numbers does not matter, so there is only 1 5-number combination from 5 numbers.
How many numbers per combination?
If the numbers can be repeated and the numbers are 0-9 then there are 1000 different combinations.
9999
There are 7 combinations. Each combination excludes a different one of the seven numbers.
If you can repeat the numbers within the combination there are 10,000 different combinations. If you cannot repeat the numbers within the combination, there are 5040 different combinations.
9
9
If numbers may be repeated . . . 36 If numbers may not be repeated . . . 30 If the sequence doesn't matter . . . 15
120 WRONG! That is the number of PERMUTATIONS. In the case of combinations, the order of the numbers does not matter, so there is only 1 5-number combination from 5 numbers.
Just one. unless you count 123456 different from 132456 then there are 46656 * * * * * But you cannot count 123456 as different from 132456 since it is NOT a different combination. And the question was about combinations.
Assuming that repeated numbers are allowed, the number of possible combinations is given by 40 * 40 * 40 = 64000.If repeated numbers are not allowed, the number of possible combinations is given by 40 * 39 * 38 = 59280.
NOT AN ANSWER:More acceptable combinations:1231 3213 2321More unacceptable combinations:1112 2222 3113Thanks.