10,000
36
You can select 9 numbers for the first digit, 8 numbers for the second digit, and 7numbers for the third digit; so 504 (e.g. 9*8*7) different three digit numbers can be written using the digits 1 through 9.
89,999 different numbers i guess
8 to the 5th power
5040 different 4 digit numbers can be formed with the digits 123456789. This is assuming that no digits are repeated with each combination.
5 x 10 x 5 = 250 different numbers, assuming there is no limit to each digits' use.
In a base-fourteen numeral system, fourteen different digits are required to represent values. These digits include the numbers 0 through 9 and the letters A, B, C, D, E, and F, which represent the values 10 through 13, respectively. Therefore, the total number of different digits needed for the base-fourteen system is 14.
A positive number is greater than a negative number. If both numbers are positive, the longer number - the one with more digits - is larger. If both have the same number of digits, compare the digits from the left, one at a time until you find one that is different. The one with the larger digit in this last comparison is the larger number.
Almost got me on this one. 20 numbers but 29 digits
There are only five distinct odd digits.
Different schemes have different id numbers of different lengths.
Using the digits 1, 3, and 5 exactly once, you can create different 3-digit numbers by permuting these digits. The number of permutations of 3 distinct digits is calculated as 3! (3 factorial), which equals 6. Therefore, the different numbers you can create are: 135, 153, 315, 351, 513, and 531. Thus, there are 6 different numbers that can be formed.