Math and Arithmetic

Statistics

Algebra

# How many different ten digit number can be formed using the digits zero until nine excluding numbers starting with zero?

###### Wiki User

###### 2007-07-05 12:36:29

If you exclude numbers starting with zero then the first digit

must be between 1 and 9 (i.e. 9 combinations). The remaining 9

digits can be any value between 0 and 9 (i.e. 10

combinations).

So you can have 9x109 = 9,000,000,000 combinations.

## Related Questions

###### Asked in Math and Arithmetic, Statistics, Algebra

### How many three digit numbers with distinct digits?

1000
there aren't even 1000 three-digit
numbers...
There are the digits 1 through 9 for the first digit. Then, we have
0 through 9 for the second digit - excluding the first digit. For
the third digit, we have 0 through 9, excluding the two previous
digits for a total of 9*9*8 =
81*8 =
648 three digit numbers with distinct digits.
EDIT- ... to be a little more specific, if your talking about a
3-digit password or unlock code its would be 1000. _-_