Each time a gamete is formed, one allele from each gene (i.e. either A or a) is included.
This means for an individual with AaBbCc, there are 8 different gametes:
ABC
ABc
AbC
Abc
aBC
abC
aBc
abc
An individual with a genotype of Aa Bb CC is able to produce how many different kinds of gametes?
The gametes form is 22 which is four types.
A B
A B ABC
A b AbC
a B aBC
a b abC
Since the genotype AaBb is heterozygous, there are four possible resulting genotypes for an offspring: AB, Ab, aB, ab. Therefore, there are four possible gametes.
In regards to these traits, two. As the first two traits will form an Ab gamete no matter what, one-half (4/8) will be AbC and the rest will be Abc.
ABC,ABc,Abc,AbC,aBC, aBc,abC, abc
Four. AB, Ab, aB, or ab.
4 can
8
Gk, gk
Yes. Remember that a heterozygote can produce two types of gametes. In this case, the unknown would produce gametes with the dominant allele A or the recessive allele a. The homozygous recessive would still only produce one kind gamete, with the recessive a allele. Therefore, we expect to see only two genotypes in the F1, Aa and aa, in equal proportions.
sexual reproduction of genotypes
No. An AA and SS combination can only produce an AS genotype.
They perform a test cross. A test cross takes the unknown genotype and crosses it with a known homozygous recessive. If the F1 generation is all dominant, then they know the organism was a homozygous recessive. If recessive offspring appear, then the organism was a heterozygote. As an example, consider a gene with two alleles, A and a, with Adominant. Now consider the test cross. The unknown genotype can only be one of two possibilities: AA (homozgous dominant) Aa (heterozygous) In a test cross,the unknown genotype is crossed with a known homozygous recessive. Since there are only two possible unknown genotypes, there can be only two possible results. First, consider the case of the unknown genotype being a homozygous dominant. The cross looks like this: AA X aa Remember that a homozygote for an allele can only produce one kind of gamete. In this case the homozygous dominant can only produce gametes with the allele A in them, while the homozygous recessive can only produce gametes with the recessive allele a in them. This means the F1 offspring can only be ONE genotype; Aa. Therefore, all of the offspring would have the dominant phenotype. Now consider the other possible cross, where the unknown genotype is heterozygous: AaX aa Remember that a heterozygote can produce two types of gametes. In this case, the unknown would produce gametes with the dominant allele A or the recessive allele a. The homozygous recessive would still only produce one kind gamete, with the recessive a allele. Therefore, we expect to see only two genotypes in the F1, Aa and aa, in equal proportions. In either case, only one test cross is needed to tell one immediately the nature of the unknown genotype. If all of the F1 are of the dominant phenotype, then the unknown genotype must be homozygous dominant; if a mixture of phenotypes appears in equal proportion, then the unknown genotype must be a heterozygote.
2 can
Literally millions of different gametes. That is why each individual is unique.
Four can be formed RY, Ry, rY and ry.
Gk, gk
Yes. Remember that a heterozygote can produce two types of gametes. In this case, the unknown would produce gametes with the dominant allele A or the recessive allele a. The homozygous recessive would still only produce one kind gamete, with the recessive a allele. Therefore, we expect to see only two genotypes in the F1, Aa and aa, in equal proportions.
Conifers produce gametes within their cones.
sexual reproduction of genotypes
The mother will produce two types of gametes: IA and IO (mother is A) The father is AB his genotype is IAIB, thus he will produce these kind of gametes: IA and IB Four combinations are possible IA from Mother and IA from Father: The child has genotype IAIA and he has blood group A IO from Mother and IA from Father: The child has genotype IAIO and he has blood group A IA from Mother and IB from Father: The child has genotype IAIB and he has blood group AB IO from Mother and IB from Father: The child has genotype IBIO and he has blood group B Thus the phnotypic ratio is blood group A:B:AB = 2:1:1
No, However humans produce skin cells by mitosis and gametes by meiosis.
No. An AA and SS combination can only produce an AS genotype.
the scrotum contains the testes, which produce gametes
Gametes are cells that each have half of the normal chromosomes of the individual they belong to. The reason for this is that during reproduction, the chromosomes in each of the gametes add together to create a full set of chromosomes. Each half a set of chromosomes comes from a different person, which is why sexual reproduction produces offspring with mixed and different traits than their parents. The gametes in males are sperm, and the gametes in females are ova(egg cells). I hope this helped out ;)