How many different types of gametes can be produced by an individual with the genotype AaBb?
Four. AB, Ab, aB, or ab.
An individual with genotype AAA will only have gametes with the genotype A. This is because the individual is homozygous.
ABc, aBc, abc, Abc. Four different gametes are formed by an individual with the genotype AaBbcc.
The possible gametes produced by an individual with the genotype Ww will be W and w.
The possible gametes are ABDEf, aBDEf, ABDef, and aBDef.
The answer is 4.
Two: TG and tG
How many genetically unique types of gametes could be produced by an individual with the genotype RrYY?
two,RY ad ry
The number of different possible gametes produced by the diploid genotype (AaBbCcDdEe) is 2 x 2 x 2 x 2 x 2 = 32 (2 for each pair of heterozygous genes).
An individual with a genotype of Aa Bb CC is able to produce how many different kinds of gametes? The gametes form is 22 which is four types. A B A B ABC A b AbC a B aBC a b abC
A gamete is simply an allele separated. Aa genotype would have gametes of A and a.
Only one, which is rY.
Since the genotype AaBb is heterozygous, there are four possible resulting genotypes for an offspring: AB, Ab, aB, ab. Therefore, there are four possible gametes.
How many unique gametes could be produced through independent assortment by an individual with the genotype AaBbCCDD?
there is no variation for the alleles C and D. alleles A and B are heterozygous there is variation for these two (Aa and Bb) 2^2=4 therefore, 4 different gametes are possible
An individual with the genotype AaBb produces four different gametes in equal proportions This is a demonstration of?
law of independent assortment b
Only one; A. At least concerning this one trait.
Half of the gametes will contain the A allele, and half will contain the a allele.
MNOPQ MNOPq MnOPQ MnOPq
two gametes (aBcD and aBcD)
How many different allele combination would be found in the gametes produced by a pea plant whose genotype was RrYY?
4 is the correct answer
If the genotype is AaBb then there will be 4 gametes produced: AB, Ab, aB, ab. Therefore the percentage of ab gametes is 25%
How many different allele combinations can be found in the gametes produced by a pea plant whose genotype is RrYY?
RY RY Yr Yr
aBCdeis the only gamete possible for this individual. This is due to the fact that all alleles at each gene locus are homozygous.
AB, Ab, aB, ab
They are all 1N (haploid) and they all come from the same individual (assuming the question is regarding the gametes produced by a single individual).
Parents with the genotype RRYy can produce two different gametes. They are RY and Ry.
How many different allele combinations would be found in the gametes produced by a pea plant whose genotype is RrYy?
It depends on the allele combinations of the other pea plant parent. If the other pea plant parent also has a genotype of RrYy, then there are 16 combinations. If the other parent has genotype RRYY, then there are only 4 allele combinations. If the other parent has a genotype of RrYY, then there are 8 allele combinations in the gametes. If the other parent has a genotype of RRYy, then there are also 8… Read More
Gametes are produced by meiosis. If the male and female gametes are produced by two different individuals, sexual reproduction combines inherited
GgM gGm MmG mMg
How many different types of gametes could be produced by an individual with the arbitrary genotype of AAbbCCDdEe?
The organism is homozygous for the A, B and C genes, so there is no variation there. Gene D and E are present in two alternative forms, so the ans will be 4(2^2)
How many genotypically different type of gametes could be produced by the individual represented by XxYYzz?
tae kayong lahat! hahahhaha
ABC,ABc,Abc,AbC,aBC, aBc,abC, abc
25% AA 50% Aa 25% AA
Ab and ab There would be about a 50/50 ratio of each.
What are the two possible gametes produced by a plant that has the genotype Aa Give the probability of each type of gamete?
A: 50% a: 50%
You need to make a Punnet Square Put A and a on top and B and B on the left side. These represent the possible gametes. Your results should be: AB AB Ba (aB) Ba (aB) So 50% of the genotype have the A allele.
Each time a gamete is formed, one allele from each gene (i.e. either A or a) is included. This means for an individual with AaBbCc, there are 8 different gametes: ABC ABc AbC Abc aBC abC aBc abc
Zygote is produced by gametes, while spore is produced by sporophytes..
Two types of gametes: AB or aB
Assuming you mean the individual is double heterzygous for genes M and T, i.e. M/m and T/t, and assuming that the genes are unlinked, equal proportions of these 4 gametes will be formed: MT, Mt, mT and mt.
How many different non repeating allele combinations can appear in the gametes of a person with the genotype AABBCc?
No. Each gamete is genetically different from the other gametes and from the parent cell.
In regards to these traits, two. As the first two traits will form an Ab gamete no matter what, one-half (4/8) will be AbC and the rest will be Abc.
Gametes are produced by meiosis
Meiosis is the process by which gametes are produced.
four genetically different cells are formed
its A, a, B, b.
gametes are produced in the ovaries and testes
How many unique gametes could be produced through independent assortment be an individual with the genotype AaBbCCddEE?
Aa=2 Bb=2 CC=1 dd=1 EE=1 2 x 2 x 1 x 1 x 1 = 4
The process of crossing over alters the genotype of gametes because when two parents create an offspring it receives genetic information of both parents.
4 The reason why the answer is 4 is because 2 of the pairs are heterozygous. When calculating possible gametes you take the number of heterozygous pairs and multiply them by each other (or raise 2 to the power equal to the number of heterozygous pairs you have). Therefore, since there are 2 heterozygous pairs in this genotype you multiply 2x2 (or 2^2).