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To find out how many different values can represented by a certain number of bits, we can use the following formula 2n-1 and that is because the first number is always a zero.

Based on that 6 bits = 26- 1= 64-1=63

7 bits= 27-1= 127

8 bits= 28-1=255

10 bits= 210-1=1023

# of bits

1=1

2=3

3=7

4=15

5=31

6=63

7=127

8=255

9=511

10=1023

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11y ago
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Q: How many different values can be represented by 6 bits 7 bits 8 bits and 10 bits?
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