32 values. 2^5=32
8192
There are 256 possible values (or characters) in 8 bits.
1200
how many bits are needed to represent decimal values ranging from 0 to 12,500?
A 128-bit register can store 2 128th (over 3.40 × 10 38th) different values. The range of integer values that can be stored in 128 bits depends on the integer representation used.
2 raised to the 8th power, or "2^8", or 256.
Eight bits to the octet. The values are 0-255.
8 bits if unsigned, 9 bits if signed
23 can be represented in binary as 10111 and would therefore require 5 bits to represent.
16 bits. Java char values (and Java String values) use Unicode.
16 of them.
In theory, 3 bits are enough to represent up to 8 (23) combinations.In theory, 3 bits are enough to represent up to 8 (23) combinations.In theory, 3 bits are enough to represent up to 8 (23) combinations.In theory, 3 bits are enough to represent up to 8 (23) combinations.