2
All should lose 2 electrons to attain the nearest noble gas configuration
Calcium will lose two electrons to gain the noble gas configuration of Argon.
Ca must lose 2 electrons to have a complete 3n shell, which has 8 valence electrons. The ion would have a charge of 2+: Ca^2+.
Calcium (Ca) typically loses 2 electrons to become more stable when bonding, as it has 2 valence electrons in its outer shell. By losing these electrons, calcium achieves a full octet, making it more stable.
Calcium (Ca) has 20 electrons and its electron configuration is [Ar] 4s². To attain a noble gas electron configuration, calcium needs to lose two electrons to achieve the stable electron configuration of argon ([Ar] 4s² 3d¹⁰).
The calcium atom (Ca) loses two valence electrons to form a calcium ion (Ca2+).
Calcium (Ca) has 20 electrons in its neutral state. To attain a noble gas electron configuration (like argon), calcium would need to lose 2 electrons to have the same electron configuration as argon, as argon has 18 electrons.
In an ionic compound, calcium (Ca) typically loses electrons. As an alkaline earth metal, calcium has two valence electrons, which it can lose to achieve a stable electron configuration. This loss of electrons results in the formation of a positively charged ion (Ca²⁺). Consequently, it often bonds with nonmetals that gain those electrons to form stable ionic compounds.
Calcium loses two electrons to obtain a noble-gas electron configuration.
Calcium is in group 2 of the periodic table, meaning that it has 2 electrons in its (outer) valence shell. So it 'only' has to lose those 2 electrons from that to acquire Argon's noble gas structure Ar(2,8,8)Ca(2,8,8,2) --> Ca(2,8,8,0)2+ + 2e-
Two
Polonium can lose two or four electrons.