Barium's atomic number is 56. Thus, barium has 56 protons and 56 electrons. Its electron configuration is 1s2 2s2 2p6 3s2 3p6 4s2 3d10 4p6 5s2 4d10 5p6 6s2. So, barium has 2 electrons in its highest energy level, level 6.
2
No. An ion is a positively or negatively charged atom, or group of atoms due to more or less electrons than necassary. Both barium and sulfate are ions, but together they are a compound, not an ion. Barium Sulfate is a chemical compound made up of two ions, a barium ion and a sulfate ion. A Barium ion is Ba+2, meaning it has two less electrons that a barium atom has. The reason for this is because the barium atom has 56 total electrons. Every atom wants to be ion with a filled valence shell, that is to have the same or similar electronic configuration of a noble gas (the elements in the right most column). The valence shell is the outermost shell of electrons and for barium the other shell is 8 electrons. In order for Barium to do this, it has to somehow lose 2 electrons to become similar to Xenon's electronic configuration. Sulfate, SO4 -2, is also an ion. the -2 means it has aqcuired 2 more electrons from another ion. It got those two electrons from the barium atom, simultaneously making the barium atom a barium ion. Sulfate is called a polyatomic ion, meaning an ion made up of more than 1 atom. When the barium ion gives the sulfate ion two electrons, thus making both electronic configurations "happy" they bond together to make an ionic bond, creating the compound barium sulfate.
In the ion of barium, two electron are lost to follow the octet rule (to have a complete valence electron shell).
Barium has two electrons in its outermost shell, electrons carrying a negative charge. When the Barium atom becomes an ion, these two electrons are lost. Now the Barium atom has more protons than electrons, meaning a net positive charge of 2.
By losing two electrons to form Ba2+ ion.
That will depend on its ionization state. Without knowing that this question cannot be answered.
Barium has 56 eletrons56 electrons and protons.
No. An ion is a positively or negatively charged atom, or group of atoms due to more or less electrons than necassary. Both barium and sulfate are ions, but together they are a compound, not an ion. Barium Sulfate is a chemical compound made up of two ions, a barium ion and a sulfate ion. A Barium ion is Ba+2, meaning it has two less electrons that a barium atom has. The reason for this is because the barium atom has 56 total electrons. Every atom wants to be ion with a filled valence shell, that is to have the same or similar electronic configuration of a noble gas (the elements in the right most column). The valence shell is the outermost shell of electrons and for barium the other shell is 8 electrons. In order for Barium to do this, it has to somehow lose 2 electrons to become similar to Xenon's electronic configuration. Sulfate, SO4 -2, is also an ion. the -2 means it has aqcuired 2 more electrons from another ion. It got those two electrons from the barium atom, simultaneously making the barium atom a barium ion. Sulfate is called a polyatomic ion, meaning an ion made up of more than 1 atom. When the barium ion gives the sulfate ion two electrons, thus making both electronic configurations "happy" they bond together to make an ionic bond, creating the compound barium sulfate.
the barium atom loses two electrons
In the ion of barium, two electron are lost to follow the octet rule (to have a complete valence electron shell).
Barium has two electrons in its outermost shell, electrons carrying a negative charge. When the Barium atom becomes an ion, these two electrons are lost. Now the Barium atom has more protons than electrons, meaning a net positive charge of 2.
Because by losing two electrons from the neutral atoms, a barium ion acquires a noble gas electron configuration.
No. Barium is a Group 2 element, and as such will lose its two valence electrons to form a Ba2+ ion when forming an ionic compound.
A neutral barium atom has 56 electrons.
A barium atom has two valence electrons.
8, since barium perchlorate is Ba(ClO4)2, and 4*2=8
By losing two electrons to form Ba2+ ion.
Barium ion = Ba2+ Hydroxide ion = OH-