Helium (He) has 2 electrons in its outer shell. Calcium (Ca) has 2 electrons in its inner shell and 8 electrons in its outer shell.
No, Ca2+ has 2 electrons LESS than Ca
Examples: Ca, Mg, Ba, Sr, Ra, etc.
To attain the noble gas configuration, Ca would have to lose 2 electrons, Mg would have to lose 2 electrons, Ba would have to lose 2 electrons, and Be would have to lose 2 electrons.
Calcium will lose two electrons to gain the noble gas configuration of Argon.
Two
Helium (He) has 2 electrons in its outer shell. Calcium (Ca) has 2 electrons in its inner shell and 8 electrons in its outer shell.
2
If 42 is the atomic number then there is 42 electrons in isotope.
Ca needs to lose 2 electrons to become Ca+2
Two.
Ca loses electrons. In general metals react in compound by losing some of their electrons, Ca is a metal.
No, Ca2+ has 2 electrons LESS than Ca
There can be 10 electrons in the n=2 shell. Two can fit in the 1s orbital, two can fit in the 2s orbital, and six can fit in the 2p orbital.
Cl-Cr-Cl
There are two valence electrons in Ca. To determine this write out the electronic configuration of Ca using the Principal quantum number method K L M N 2 8 8 2 as you can see the number of electrons in the outermost shell (which is the valency) is 2. Making Ca a metal and giving away its 2q outermost electrons to attain a stable electronic configuration.
n1= 25 n2= n1+1 n3= n1-1 n4=n1+2 n5=n1-2