Usually three will be lost.
I believe 4s2 is the distinguishing (last) electron
Only three electrons.
Yttrium (Y) has, for the most part, 39 electrons. In its ion (atom with a charge that has lost or gained electrons) form though, it has 36 electrons.
In the ion of barium, two electron are lost to follow the octet rule (to have a complete valence electron shell).
Scandium (Sc) has an atomic number of 21, which means it has 21 electrons. Its electron configuration is [Ar] 3d¹ 4s². In this configuration, there is one unpaired electron in the 3d subshell, as the 4s subshell is fully paired. Therefore, scandium has one unpaired electron.
Scandium has 3 valence electrons.
Scandium has 3 valence electrons.
There is zero NET loss or gain of electrons
Scandium has 1 3d electron.
The element scandium has 21 electrons. However, most of these occupy the inner orbitals. The only electrons in the valence shell are those in the 2s orbital. Since there are two such electrons, scandium has 2 valence electrons.
Scandium typically has 21 electrons in a neutral atom. In an Sc3+ ion, it loses 3 electrons, so the ion would have 18 electrons.
You can determine how many electrons are gained or lost by looking at the atom's charge. If the atom gains electrons, it becomes negatively charged; if it loses electrons, it becomes positively charged. The difference between the atom's original and final charge tells you how many electrons were gained or lost.
I believe 4s2 is the distinguishing (last) electron
Only three electrons.
the oxidation number
-3 electrons are gained,i.e,3 electrons are lost by Al and 3 electrons are gained by the other atom nearby.
If there are 4 electrons and 4 protons, the atom is electrically neutral since the positive charges from the protons balance out the negative charges from the electrons. No electrons are lost or gained in this scenario.