Usually three will be lost.
Only three electrons.
I believe 4s2 is the distinguishing (last) electron
It should loose 2 electrons to become a noble gas.
Yttrium (Y) has, for the most part, 39 electrons. In its ion (atom with a charge that has lost or gained electrons) form though, it has 36 electrons.
In the ion of barium, two electron are lost to follow the octet rule (to have a complete valence electron shell).
it has gain 4 electrons
-3 electrons are gained,i.e,3 electrons are lost by Al and 3 electrons are gained by the other atom nearby.
two electrons lost
Scandium has 1 3d electron.
There is zero NET loss or gain of electrons
Xe neither gain or lose electrons= 0
1 Electronic configuration of scandium: [Ar]3d1.4s2.
Only one electron lost.
The element scandium has 21 electrons. However, most of these occupy the inner orbitals. The only electrons in the valence shell are those in the 2s orbital. Since there are two such electrons, scandium has 2 valence electrons.
Only three electrons.
the oxidation number
There are many factors when it comes to Boron. If it were to form an Ion, then it would drop a total of three electrons.