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Cl has 7 valence electrons.
Chlorine will not for Cl-7 ion. It will form Cl-1 ion, which has total of 18 electrons.
Cl has 7 electrons. If you draw Cl^-, there are 8 electrons and a minus 1 charge. What do you want to draw? And what do you mean by "odd" electrons?
Chloride anion has 8 valence electrons.
Chlorine is a metal element. There are 17 electrons in a single atom.
Cl has 7 valence electrons.
Chlorine will not for Cl-7 ion. It will form Cl-1 ion, which has total of 18 electrons.
Cl has 7 electrons. If you draw Cl^-, there are 8 electrons and a minus 1 charge. What do you want to draw? And what do you mean by "odd" electrons?
None - however Chlorine, (Cl) when in the ionic state Cl- does.
Chlorine (Cl) has 17 electrons in its shells.
In cl-cl bond 1 electron is sahred by each of Cl atom.
Chlorine has total of 17 electrons
Chloride anion Cl- has the same electron configuration as Argon (its succeding noble gas) so:Cl- has 18 electrons configured like: 1s2, 2s2 2p6, 3s23p6
The number of electrons is 18.
Chloride anion has 8 valence electrons.
Since Be is in the 2nd group, it should have 2 valence electrons and Cl should have 7 (in 7th group), and since there is 2 Cl, then there is 14. Add 14 Cl electrons and 2 Be electrons to get 16 electrons (valence, not total)
Just 1.