Assuming constant rate of deceleration, then the formula is:
x = vavet
x = distance
vave = average velocity
t = time
vave = (v1 + v2)/2
v1 = 65 mph
v2 = 35 mph
vave = (65 mph + 35 mph)/2 = 50 mph
You are going to have to know another bit of information, which is the braking ability of the vehicle, in order to get t. For example, if the braking ability is -10mph/sec, then calculate that to reduce by 30 mph would take 3 seconds. I will use 3 seconds to continue the calculations.
x = 50mph X 3 sec X 5280 feet/mile / 60 sec/min / 60 min/hour = 220 feet
Remember that this is just an example. The actual distance depends upon the braking ability of your vehicle.
35 mph = 51.33 feet per second.
At 35 mph you will travel about 154 feet in three seconds.
146.66 feet every 10 seconds at 10 mph.
When traveling at 35 mph it will take you 210 feet to come to a complete stop.
When traveling at 35 mph it will take you 210 feet to come to a complete stop
35 feet per second = 23.9 mph
35 mph = 51.3 feet per second.
35 mph = 3,080 feet per minute.
That question has many variables that must be known to give a 100% correct answer. (Weight or car, brake capability, surface driving on, ect.)
35 feet at 30 mph requires about 0.8 seconds.
It takes 51.43 seconds to travel 2,640 feet at 35 mph.
0.009 of a mile or about 47 feet