1 ft = 12 inch
60 inch = (60/12) = 5 ft
(1500 pounds) x (5 ft) = 7,500 foot-pounds
The question was going along so nicely there, until it got to the very end, and thenshot itself in the foot with "foot pounds"."Foot pounds" is a torque, not a force.-- If you apply 50 pounds of force at the end of the crank, that 50 pounds becomes175 pounds of force at the surface of the 8-inch cylinder, because the mechanicaladvantage of the crank/cylinder arrangement is 28/8 = 3.5 .-- If you apply 50 foot-pounds of torque at the end of the crank, then the force is50 ft-lb/28 inches = 50 lb x 12 in/28 in = 21 3/7 pounds .Now, the same mechanical advantage of 3.5 gives you 75 pounds at the hub.What a difference a unit makes !
80 lbs until past 45 degrees
1 horsepower = 550 foot-pounds per second 30 inches = 2.5 feet (2.5) x (220)/10 = 550 foot pounds per 10 seconds = 1/10th of a horsepower.
Macho Matt can lift 200 kilograms with ease. How much is this in pounds?
a foot pound is a measure of torque, or turning power. Imagine a wrench that is positioned on a nut, the handle of which is exactly one foot long from the center of the nut and is also perfectly horizontal. Now put one pound of downforce on the end of the wrench handle. You now have one foot-pound of torque on the nut. This unit of measurement is how torque is calculated in an automobile.
(1,500 pounds) x (60 inches) / (12 inches per foot) = 7,500 foot-pounds
1500 or less
4,000 foot pounds of energy (work) for each foot highyou lift it off the ground,regardless of whether you do it with a lever, a pulley, a jack, a hydraulic lift, oryour bare hands.
The question was going along so nicely there, until it got to the very end, and thenshot itself in the foot with "foot pounds"."Foot pounds" is a torque, not a force.-- If you apply 50 pounds of force at the end of the crank, that 50 pounds becomes175 pounds of force at the surface of the 8-inch cylinder, because the mechanicaladvantage of the crank/cylinder arrangement is 28/8 = 3.5 .-- If you apply 50 foot-pounds of torque at the end of the crank, then the force is50 ft-lb/28 inches = 50 lb x 12 in/28 in = 21 3/7 pounds .Now, the same mechanical advantage of 3.5 gives you 75 pounds at the hub.What a difference a unit makes !
Yes. Work is measured in foot-pounds, so 300*1 = 100*3 = 300 foot-pounds. ■
33" tire is what we recomend
you shoul only need to extend you body to frame grounds. but generally that is only with a big lift
yes you can run 35inch tire as long as you put them on an 8inch rim. i have that size on my 1999 dodge ram 1500 4 door.
you shouldn't have to use any lift at all. i have 24s on my 2000 1500 ext. cab and have no trouble with rubbing. doesnt like to stop though
That takes 80 foot-pounds, equivalent to about 59 joules.
800
4 inch body lift or 6 inch frame lift