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How many pounds can you lift with a 28 inch crank type handle turning an 8 inch round cylinder attached by a rope with a force of 50 foot pounds?
Wiki User
∙ 11y ago
The question was going along so nicely there, until it got to the very end, and then
shot itself in the foot with "foot pounds".
"Foot pounds" is a torque, not a force.
-- If you apply 50 pounds of force at the end of the crank, that 50 pounds becomes
175 pounds of force at the surface of the 8-inch cylinder, because the mechanical
advantage of the crank/cylinder arrangement is 28/8 = 3.5 .
-- If you apply 50 foot-pounds of torque at the end of the crank, then the force is
50 ft-lb/28 inches = 50 lb x 12 in/28 in = 21 3/7 pounds .
Now, the same mechanical advantage of 3.5 gives you 75 pounds at the hub.
What a difference a unit makes !
Wiki User
∙ 11y ago
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