A good estimate is somewhere between 4 1/2 and 5 gallons in 60 lb of dry sand, depending on how tightly it is packed and how fine the grains are. .
The answer will depend on how deep a layer of sand.
7.5 gal
No useful answer can be given without the necessary detail.The question needs to describe whether the cement alone will be used (or whether it will be used with sand, or with sand and aggregate, and what mix ratios), and the depth of the application.
60- 100 Gal.
50-60
Depends on the type of sand also if it is wet or dry
(2 pt/min) * (1 gal / 8 pt) * (60 min/hr) = (2 * 1 * 60 * pt * gal * min) / (8 * min * pt * hr) = 15 gal/hr
227L equates to about 60 (59.9670554) US gallons.
Divide 60 lbs of solvent by 75 gal of paint to find how much solvent per gal of paint, then multiply by 90 to find how much solvent you need for 90 gal of paint: 60 / 75 = .8 lbs solvent per gal of paint; .8 x 90 = 72 lbs of solvent needed for 90 gal of paint.
yumm i really want some hershey kisses right now =] and there are about 3421 in a 60 oz bag
A 60 gallon tank?
48