The pond is a cylinder;
radius = ½ × diameter
volume_cylinder = π × radius² × height
→ volume_pond = π × (½ × 5 ft)² × 1 ft = 25π/4 ft³ ≈ 19.63 ft³
Converting this to gallons depends where you are:
* In UK:
1 ft³ ≈ 6.23 imp gal
→ 19.63 ft³ ≈ 19.63 × 6.23 imp gal ≈ 122.3 imp gal
* In USA:
1 ft³ ≈ 7.48 US gal
→ 19.63 ft³ ≈ 19.63 × 7.48 US gal ≈ 146.9 US gal
(Other countries probably use the same as the UK: the imperial gallon.)
The aquarium would have a volume of 2200 cubic inches. One cubic inch is 0.0043290 liquid gallons, so 2200*0.0043290 = 9.52381 gallons.
27 inches deep.
21.76 US gallons of water.
3400 gal
None. A hole is the absence of the material.
You need to tell us how deep it is.
15 foot round? About 5000 gallons, if it's four feet deep. Here's a formula for round pools: distance across*distance across*depth*5.9 for rectangles: length*width*depth*7.5 or for a deep end: length*width*((shallow end depth + deep end depth)/2)*7.5
A 100-foot round pool filled with 1.5 feet of water would be holding about 88,500 gallons.
A round pool 8 feet across and 18 inches deep holds up to 2,857.5 gallons of water.
You haven't told us how long the trough is, or how deep the water is in it. If it's full to the rim ... 2-ft deep ... then there's 44.88 gallons for every foot of the trough's length.
You need one more measurement; 18.5 ft long by 4.5 ft deep by how wide? Or if it is a circular pool, you need to specify that.
A 12-foot wide round pool with 3.3 feet of water contains 2,803.7 gallons of water.