You can use the volumetric equations. To break them down simply: Volume = Width * Height * Depth Width * Height = Area Area of a circle = Pi * radius2 Okay, so now that we have remembered the formulas, we can plug in the numbers: Radius = 15/2 or 7.5 feet so Area = 3.14159265 (Pi) * 7.52 which equals 176.715 sqare feet Now, Volume = Area * Depth, so 176.7145868 (the area) * 4 = 706.858347 cubic feet. 1 gallon = 0.13368 cubic feet, so take 706.858347/0.13368 to get the answer: A 15 foot round above ground swimming pool that is 4 feet deep will hold 5,287.6676 gallons of water.
24' x 4' round above ground holds 14,000 gallons
To calculate this the depth would also be needed
13,346 gallons per vertical foot.
An 18' Round 52" wall above ground pool holds approximately 7300 gallons
It depends. How deep is the pool?
A round pool that is 16 feet across and is filled with 48 inches of water will contain about 6,041 gallons of water.
http://www.worldofwater.com/pond_volume.htm This website is for ponds but the formula is the same to determine volume.
Just a little over 6,000 gallons.
8000 Gallons -- ANSWER -- For every foot of water in the pool there is 1,585 imperial gallons.
If it is 4 feet deep, then 13,500 gallons
A 21' pool that is 48" high should have 10,407 gallons of water (approx). To calculate the gallons in a round swimming pool use this formula: Length x length x average depth x 5.9 = gallons of pool So in your case 21 x 21 x 4 x 5.9 = 10,407 gallons
Well my pool is 14' round an 36" deep an it took 2200 gallons so your probably looking at around 5000 gallons.
If it is a round 18' in diameter and a constant 52" deep then the volume is 158.6 gallons per inch. 52 inches would then be 8247.2 gallons.