Approximately 14645 gallons. Let's suppose that this pool is a perfect cylinder shape of 24 ft. diameter by 52 inches (or 4 1/3 feet) deep. The formula to find the volume of a cylinder is V=πr(square)h. We could use 3.14 to represent Pi (π), r(square) is 144 and the height of 52 inches, which is 4and1/3 feet. So then just multiply 3.14 (π) times 144 times 4 and a third. The answer is approximately 1958 cubic feet. Since there are 7.481 gallons of liquid per cubic foot, 7.481 times 1958 is approximately 14645 gallons.
Here's a formula for round pools:
distance across*distance across*depth*5.9
for rectangles:
length*width*depth*7.5
or for a deep end:
length*width*((shallow end depth + deep end depth)/2)*7.5
Assuming you are talking about a round pool, we have:
24*24*4.3*5.9
or about 15,000 gallons
24*12= 288 inches 288"/pi
91.673"/2
45.8365" = radius of pool
V=pi*r2H
V=3.14159 * 45.8365"2 * 52"
V=143.99949"2 * 52"
V=20935.85313" * 52"
V=1078264.363"
1078264.363"3 / 12 = 89855.36356'3
1 foot3 = 7.48051948 U.S. gallons:
89855.36356'3 * 7.481 = 672207.9748 gallons
Answer = 672207.9748 gallons
This seems like an outrageously high number, so if anyone wants to check the math, you have no argument from the answerer
14,715 gallons are required.
About 12,365 gallons.
14663
11,200
2300
If 20' is the circumference, then the answer is 833.4 gallons.
6015.77 gallons
70
It is 30.6 cubic feet = 190.3 Imperial gallons.
'bout 1500 to 2000
There is NO way to calculate this without knowing how deep the pool is filled!
A round swimming pool 12 feet across by 4 feet deep will hold 452 ft3 which converts to 3,381 gallons
About 7,650 gallons.
489.76 gallons of water.
6,200 gallons.
181,248 gallons.
3,398.4 gallons.