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Approximately 14645 gallons. Let's suppose that this pool is a perfect cylinder shape of 24 ft. diameter by 52 inches (or 4 1/3 feet) deep. The formula to find the volume of a cylinder is V=πr(square)h. We could use 3.14 to represent Pi (π), r(square) is 144 and the height of 52 inches, which is 4and1/3 feet. So then just multiply 3.14 (π) times 144 times 4 and a third. The answer is approximately 1958 cubic feet. Since there are 7.481 gallons of liquid per cubic foot, 7.481 times 1958 is approximately 14645 gallons.

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9y ago
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Wiki User

15y ago

Here's a formula for round pools:

distance across*distance across*depth*5.9

for rectangles:

length*width*depth*7.5

or for a deep end:

length*width*((shallow end depth + deep end depth)/2)*7.5

Assuming you are talking about a round pool, we have:

24*24*4.3*5.9

or about 15,000 gallons

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14y ago

24*12= 288 inches 288"/pi

91.673"/2

45.8365" = radius of pool

V=pi*r2H

V=3.14159 * 45.8365"2 * 52"

V=143.99949"2 * 52"

V=20935.85313" * 52"

V=1078264.363"

1078264.363"3 / 12 = 89855.36356'3

1 foot3 = 7.48051948 U.S. gallons:

89855.36356'3 * 7.481 = 672207.9748 gallons

Answer = 672207.9748 gallons

This seems like an outrageously high number, so if anyone wants to check the math, you have no argument from the answerer

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Wiki User

9y ago

14,715 gallons are required.

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Wiki User

9y ago

About 12,365 gallons.

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Wiki User

11y ago

14663

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Wiki User

7y ago

11,200

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Anonymous

Lvl 1
4y ago

2300

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Q: How many gallons of water are in a 24 foot round by 52 inch deep swimming pool?
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