26700 gallons
That will depend on how deep you want the water to be.
It depends how deep it is.
You didn't mention shape, however if a rectangle it would be approximately 7,300 gallons
Based on a rectangle. approx 20,250 gallons
This pool can hold up to about 7,181 gallons of water.
Assuming it is a rectangle, 56.232 imperial gallons
Assuming brim-full, 30x3 = 90 ft2 30x4/2= 60ft2 90+60=150ft2 150x15=2250ft3 2250ft3 = 14014.8675 UK gallons 2250ft3 = 16831.17 US gallons Answer: area on top = (18x36) ft squared = 648 ft^2 vol of top section = 648x3 = 1944ft^3 vol of (bottom) diagonal section is: 0.5(36x18).(8-3) = 1620ft^3 total vol = 1944 + 1620 = 3564ft cubed 3564 (feet cubed) = 22 199.5604 Imperial gallons what I did was split the volume of the pool into two sections and deal with them independently as two separate shapes.
You would have to know how deep the tank is.
If the bottom of the pool is a uniform gradient from one side of the rectangle to the other, then volume = 2625 cubic feet = 16351 gallons.
Length x width x average depth*. Multiply result by 7.48 to determine volume in gallons.* 'average depth' is shallow end + deep end divided by two
box = 18 x 36 x 3 = 1944 cu ft wedge = 1/2 x 5 x 36 x 18 = 1620 cu ft total = 3564 cu ft = 26661 us gal
Need to know the depths of the shallow and deep end, and the shape of the pool, whether it is a rectangle or kidney or irregular shaped.