In order to figure this out, you must do dimensional analysis. Here it is:
3.0 moles He x 4.0026 grams/ mole He = 12 grams
To find the number of moles of hydrogen gas, we first need to convert the mass of hydrogen gas from grams to moles using the molar mass of hydrogen gas (2 g/mol). 5.04 grams of hydrogen gas is equal to 5.04 g / 2 g/mol = 2.52 moles of hydrogen gas.
To find the weight of 2350 L of O2 gas at STP, you would first need to calculate the moles of gas using the ideal gas law. Then, use the molar mass of O2 to convert moles to grams. The molar mass of O2 is 32 g/mol, so you would multiply the moles by 32 g/mol to find the weight in grams.
No, you do not need to convert grams to moles when using the ideal gas law. The ideal gas law is typically used with moles of gas, but you can directly use grams by adjusting the units of the gas constant accordingly.
The balanced chemical equation for the reaction between oxygen and hydrogen is2H2 + 02 -> 2H2OThus 2.2 moles of oxygen reacts with 4.4 moles of hydrogen to form 4.4 moles of steam (water in gaseous state).The mass of H2O obtained is thus 4.4 x 18.0 = 79.2g.
four moles. Approximately. Oxygen has a molecular weight of 16.0 grams per mole so 64 grams divided by 16.0 grams per mole is four moles.
The answer is 2 moles.
To find the number of moles of hydrogen gas, we first need to convert the mass of hydrogen gas from grams to moles using the molar mass of hydrogen gas (2 g/mol). 5.04 grams of hydrogen gas is equal to 5.04 g / 2 g/mol = 2.52 moles of hydrogen gas.
6,5 moles oxygen equals 208 g.
To find the weight of 2350 L of O2 gas at STP, you would first need to calculate the moles of gas using the ideal gas law. Then, use the molar mass of O2 to convert moles to grams. The molar mass of O2 is 32 g/mol, so you would multiply the moles by 32 g/mol to find the weight in grams.
No, you do not need to convert grams to moles when using the ideal gas law. The ideal gas law is typically used with moles of gas, but you can directly use grams by adjusting the units of the gas constant accordingly.
The balanced chemical equation for the reaction between oxygen and hydrogen is2H2 + 02 -> 2H2OThus 2.2 moles of oxygen reacts with 4.4 moles of hydrogen to form 4.4 moles of steam (water in gaseous state).The mass of H2O obtained is thus 4.4 x 18.0 = 79.2g.
four moles. Approximately. Oxygen has a molecular weight of 16.0 grams per mole so 64 grams divided by 16.0 grams per mole is four moles.
Mass (g) = Mr * Moles If you rearrange it, you get Moles = Mass/Mr Working with a 2dp periodic table you get: Moles = 2/1.01 =1.98 There are 1.98 moles of hydrogen in 2g of H2 gas.
0.560 moles × 35.453 grams/mole = 19.85 grams
To determine the mass of oxygen gas containing the same number of moles as 56 grams of sulfur, calculate the molar mass of sulfur (32 g/mol) and use it to find the number of moles in 56 grams. Then, since the molar ratio of sulfur to oxygen in a compound is 1:1, this same number of moles of oxygen gas would weigh 32 grams.
To find the number of moles in 5.67 grams of fluorine gas, you need to divide the mass by the molar mass of fluorine. The molar mass of fluorine is approximately 19 g/mol. Therefore, 5.67 grams of fluorine gas is equal to 5.67 g / 19 g/mol ≈ 0.298 mol.
To find the number of moles in 18.0 grams of hydrogen gas, you need to divide the given mass by the molar mass of hydrogen gas. The molar mass of hydrogen gas (H2) is about 2.016 grams/mol. So, 18.0 grams / 2.016 grams/mol ≈ 8.93 moles of hydrogen gas.