Yes. You should convert grams to moles in order to use the ideal gas law. The units of the other variable, R (gas constant) has moles in it.
number of moles of gas particles
5 moles
First we need the moles of krypton gas. Monoatomic gas.0.405 grams Kr (1 mole Kr/83.80 grams)= 0.004833 moles krypton gas======================Now the ideal gas equation.PV = nRT(1 atm)(X volume) = (0.004833 moles Kr)(0.08206 L*atm/mol*K)(298.15 K)= 0.118 Liters of krypton gas--------------------------------------
.298 Moles
The number of moles in exactly 84 grams of chlorine (Cl2) gas 2,37.
First, find out what the temperature and pressure of the gas is. Next, determine the mass per mole - this one I'll give you, it's 58.12 grams per mole. Divide 76 by 58.12 to get the number of moles of gas you have. Then, use the ideal gas law to determine the number of liters of gas per mole at the temp and pressure your gas is. Finally, multiply the liters per mole by the number of moles you have, and you've got it.
number of moles of gas particles
5 moles
First we need the moles of krypton gas. Monoatomic gas.0.405 grams Kr (1 mole Kr/83.80 grams)= 0.004833 moles krypton gas======================Now the ideal gas equation.PV = nRT(1 atm)(X volume) = (0.004833 moles Kr)(0.08206 L*atm/mol*K)(298.15 K)= 0.118 Liters of krypton gas--------------------------------------
.298 Moles
Use the ideal gas law, PV=nRT. P= pressure V= volume n= number of moles R= gas law constant T= temperature If you have P, V, R, T then you can solve for "n" to find the number of moles. There are a number of ways and variations that you can go about finding the number of moles, but all would involve the ideal gas law or a similar formula.
0.560 moles × 35.453 grams/mole = 19.85 grams
molar weight of N = 14 grams/mole 35.7 grams/14 grams/mole = 2.55 moles
The answer is 2 moles.
The number of moles in exactly 84 grams of chlorine (Cl2) gas 2,37.
Use equation n=PV/RT where n is number of moles and R is gas constant. Use R= .8314 L-Atm/mol-K. convert 3 ml to liters(3/1000) and 100C to Kelvin (100+273) and solve for moles. Convert moles to grams. 1 mol of N2 equals 28 grams
First find moles hydrogen gas. 20 grams H2 (1 mole H2/2.016 grams) = 9.921 moles H2 Now, the ideal gas equation. PV = nRT (1 atm)(volume L) = (9.921 moles H2)(0.08206 L*atm/mol*K)(298.15 K) Volume of hydrogen gas = 243 Liters ----------------------------------------------------