Use the ideal gas law, PV=nRT.
P= pressure
V= volume
n= number of moles
R= gas law constant
T= temperature
If you have P, V, R, T then you can solve for "n" to find the number of moles. There are a number of ways and variations that you can go about finding the number of moles, but all would involve the ideal gas law or a similar formula.
You divide the liters of gas by 22.4 to convert to moles. This is because one mole of gas at standard temperature and pressure (STP) occupies 22.4 liters.
22.414dm-3*5.5=123.277dm-3
What you need to know to work this out is that:- Moles of gases at standard temperature pressure (With P and T constant) are proportional to the volume they occupy, divided by their specific gas constant.
The volume of a gas depends on its pressure, temperature, and volume according to the ideal gas law PV = nRT. Without knowing the pressure, temperature, or container size, it's not possible to determine the volume occupied by the 0.48 moles of hydrogen.
Pressure, volume and temperature, and moles of gas are the four principal variables to describe a gas (for example, see related questions on Ideal Gas Law and others). The standard units are: Pressure: atmospheres (atm) Volume: liters (L) Temperature: Kelvin (K) Number of moles are measure in, well, moles.
For chemistry, after IUPAC rules the standard temperature is 0 oC and the standard pressure is1 bar.
You divide the liters of gas by 22.4 to convert to moles. This is because one mole of gas at standard temperature and pressure (STP) occupies 22.4 liters.
To determine the number of moles of argon gas required to fill a volume of 116.7 L, we first need to convert the volume to liters. Using the ideal gas law equation, PV = nRT, where P is pressure, V is volume, n is the number of moles, R is the ideal gas constant, and T is temperature, we can calculate the number of moles. Given that argon gas is at STP (standard temperature and pressure), we can use the standard values of 1 atm for pressure and 273 K for temperature.
The volume that 2.4 moles of chlorine gas would occupy depends on the temperature and pressure of the gas, according to the ideal gas law (PV = nRT). At standard temperature and pressure (STP), which is 0°C and 1 atm pressure, 2.4 moles of chlorine gas would occupy approximately 53.75 liters.
1 mole of any gas occupies 22.4 L at standard temperature and pressure (STP). Therefore, 8.08 L of O2 at STP would contain 8.08/22.4 = 0.36 moles of O2.
210.3 moles of H2 are contained in one gallon of H2O
22.414dm-3*5.5=123.277dm-3
What you need to know to work this out is that:- Moles of gases at standard temperature pressure (With P and T constant) are proportional to the volume they occupy, divided by their specific gas constant.
we first find the number of moles( number of moles= mass/molar mass). the we can find the volume by using the formule( volume=number of moles multiplyd by the molar volume)
The volume of a gas depends on its pressure, temperature, and volume according to the ideal gas law PV = nRT. Without knowing the pressure, temperature, or container size, it's not possible to determine the volume occupied by the 0.48 moles of hydrogen.
The volume of hydrogen is 97, 86 L.
At standard temperature and pressure (STP), one mole of a gas is 22.4L. So, in order to determine how many moles of O2 are in 30L, you do the following: multiply 30L O2 x 1mol O2/22.4L O2, which equals 1.34mol O2.