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How many atoms are present in 8.00 moles of chlorine?
If the chlorine is in its normal state of diatomic molecules, there are 16.0 moles of chlorine atoms in 8.00 moles of chlorine. The number of atoms is then 16 times Avogadro's number = 9.64 X 1024, to the justified number of significant digits.
How many molecules of chlorine are in 134.5 grams of chlorine?
http://en.wikipedia.org/wiki/Chlorine 1 mol of chlorine (Cl2) weighs (2*35.45 =)70,90 grams 134,5 grams of chlorine is (134,5/70,9 =) 1,897 mol of chlorinegas. 1,897 * 6,02 * 10^23 = 1,142 * 10^24 molecules of Cl2
The density of carbon tetrachloride is 1.59 g per ml How many chlorine atoms are present in 55 ml of carbon tetrachloride?
There are 4 chlorine atoms in a molecule of carbon tetrachloride. Calculate the number of moles of carbon tetrachloride in 55 ml using the density provided. Then use Avogadro's number (6.022 x 10^23) to determine the number of chlorine atoms present.
How many molecules of ammonia are contained in 10 moles of ammonia NH3?
1 mol of any substance contains 6.02 x 1023 constituent particles. This is the avogadro constant. So in 10 moles of NH3, there would be 10 x 6.02 x 1023 = 6.02 x 1024 NH3 molecules.
How many moles are in 1.204x1024 atoms of Calcium?
The formula unit for calcium is a single atom. Therefore, the number of moles may be found by dividing the given number of atoms by Avogadro's number, or 1.999 moles.
How many atom are in 7.2mol of chlorine?
There are approximately 4.34 x 10^24 atoms in 7.2 moles of chlorine, which is calculated by multiplying Avogadro's number (6.022 x 10^23 atoms/mol) by the number of moles.
How many atoms are present in 8.00 moles of chlorine?
If the chlorine is in its normal state of diatomic molecules, there are 16.0 moles of chlorine atoms in 8.00 moles of chlorine. The number of atoms is then 16 times Avogadro's number = 9.64 X 1024, to the justified number of significant digits.
How many molecules of chlorine are in 134.5 grams of chlorine?
http://en.wikipedia.org/wiki/Chlorine 1 mol of chlorine (Cl2) weighs (2*35.45 =)70,90 grams 134,5 grams of chlorine is (134,5/70,9 =) 1,897 mol of chlorinegas. 1,897 * 6,02 * 10^23 = 1,142 * 10^24 molecules of Cl2
What will be the volume occupied by one molecule of water at stp?
At STP, water is a liquid with a density of 1000.000 grams per liter. The gram molecular mass of water is 18.01528. Therefore, the number of moles of water in one liter is 1000.000/18.01528 or 55.5084 moles. The number of molecules in one liter is therefore 55.5084 X 6.022 X 1023 or about 3.34272 X 1025, and the volume of one molecule is therefore 1 [exact]/3.34272 X 1025 or 2.99158 X 10-24 liter.
How many atoms of chlorine are there in 445g of lead 2 chloride?
445g PbCl2 x 1 mol PbCl2 x 6.022x10^23 atoms PbCl2------------- ----------------- ------------- =278g PbCl2 1 mol PbCl2when multiplied through it equals 9.63975885 x 10^23formatting sucks sorry :)
How many molecules are there in 18.9 moles of chlorine gas?
One mole is 6.022 × 1023 (or 602,200,000,000,000,000,000,000) bits of anything. You have 18.9 moles. Thus: 18.9 × (6.022 × 1023) = 1.138158 × 1025 (or 11,381,580,000,000,000,000,000,000) molecules Cl2.
How many moles of carbon are in 2moles of sugar?
There are 24 moles of Carbon (C) in 2 moles of table sugar (sucrose)
How many moles of NCl3 contain 2.55x1024 chlorine atoms?
To find the number of moles of NCl₃ containing 2.55 x 10²⁴ chlorine atoms, we first note that each molecule of NCl₃ contains 3 chlorine atoms. Therefore, the number of NCl₃ molecules can be calculated by dividing the number of chlorine atoms by 3: [ \frac{2.55 \times 10^{24}}{3} = 8.50 \times 10^{23} \text{ molecules of NCl}_3. ] Next, to convert molecules to moles, we use Avogadro's number (6.022 x 10²³ molecules/mol): [ \frac{8.50 \times 10^{23}}{6.022 \times 10^{23}} \approx 1.41 \text{ moles of NCl}_3. ] Thus, there are approximately 1.41 moles of NCl₃ in 2.55 x 10²⁴ chlorine atoms.
What is the volume of 1.51 10 24 atom of an unknown gas STP?
You need to apply the equation pV = nRT p = Pressure (1x10^5 Pa at STP) n = Number of moles (1.51x10^24 / 6.02x10^24) T = Temperature (273 K at STP) R = Universal gas constant (8.31) This gives the volume as 0.005 m^3
What is the molarity of 48.6 grams of magnesium?
To find the molarity of 48.6 grams of magnesium, you first need to determine the number of moles of magnesium in 48.6 grams using the molar mass of magnesium (24.305 g/mol). Then, you divide the moles of magnesium by the volume of the solution in liters to get the molarity.
What mass of KMnO4 is required to prepare 3.00 liters of a 0.05253 M solution of KMnO4?
To find the mass of KMnO4 needed, you can use the formula: mass = molarity x volume x molar mass. First, calculate the moles of KMnO4 using moles = molarity x volume. Then, multiply the moles by the molar mass of KMnO4 to find the mass needed.
The density of carbon tetrachloride is 1.59 g per ml How many chlorine atoms are present in 55 ml of carbon tetrachloride?
There are 4 chlorine atoms in a molecule of carbon tetrachloride. Calculate the number of moles of carbon tetrachloride in 55 ml using the density provided. Then use Avogadro's number (6.022 x 10^23) to determine the number of chlorine atoms present.
