If the chlorine is in its normal state of diatomic molecules, there are 16.0 moles of chlorine atoms in 8.00 moles of chlorine. The number of atoms is then 16 times Avogadro's number = 9.64 X 1024, to the justified number of significant digits.
The number of chlorine atoms in 2,00 moles of CCl4 is 48,113.10e23.
Avogadro's numbers worth. I mole of anything is, 6.022 X 1023 atoms ----------------------------
9.02 X 10^23 atoms Cl2 (1mol Cl2/6.022 X 10^23) = 1.50 moles Cl2
To find the number of moles of PCl3, you need to first calculate the number of moles of Cl atoms in 3.68 * 10^25 atoms. There are 3 Cl atoms in each molecule of PCl3, so you divide the number of Cl atoms by 3 to get the number of moles of PCl3.
There are 2.21 x 10^24 atoms of phosphorus in 3.65 moles of phosphorus triiodide.
The number of chlorine atoms in 2,00 moles of CCl4 is 48,113.10e23.
To find the number of moles of atoms in 75.10 grams of chlorine, you need to first determine the molar mass of chlorine. Chlorine has a molar mass of approximately 35.45 g/mol. Next, you can use the formula Moles = Mass / Molar Mass to calculate the moles of chlorine atoms in 75.10 grams. This would result in approximately 2.12 moles of chlorine atoms.
Since chlorine gas is a diatomic molecule (Cl2), one mole of chlorine gas contains two moles of chlorine atoms. Therefore, 6.00 moles of chlorine atoms would be equivalent to 3.00 moles of chlorine gas.
Avogadro's numbers worth. I mole of anything is, 6.022 X 1023 atoms ----------------------------
In one mole of aluminum chloride (AlCl₃), there are three moles of chlorine atoms. This is because each formula unit of AlCl₃ contains three chlorine (Cl) atoms. Therefore, in one mole of AlCl₃, there are 3 moles × 6.022 × 10²³ (Avogadro's number) = 1.8066 × 10²⁴ chlorine atoms.
9.02 X 10^23 atoms Cl2 (1mol Cl2/6.022 X 10^23) = 1.50 moles Cl2
0.0845 moles of tungsten is equal to 0,50887.10e23.
445g PbCl2 x 1 mol PbCl2 x 6.022x10^23 atoms PbCl2------------- ----------------- ------------- =278g PbCl2 1 mol PbCl2when multiplied through it equals 9.63975885 x 10^23formatting sucks sorry :)
To find the number of moles of Cl₂ in 985 g, use the molar mass of Cl₂, which is about 70.906 g/mol. The number of moles is calculated by dividing the mass by the molar mass: [ \text{moles of Cl₂} = \frac{985 \text{ g}}{70.906 \text{ g/mol}} \approx 13.9 \text{ moles} ] Since Cl₂ consists of two chlorine atoms, the mass of Cl atoms present can be calculated by multiplying the moles of Cl₂ by 2 and then by the molar mass of chlorine (approximately 35.453 g/mol), resulting in approximately 985 g of Cl atoms.
There are approximately 4.34 x 10^24 atoms in 7.2 moles of chlorine, which is calculated by multiplying Avogadro's number (6.022 x 10^23 atoms/mol) by the number of moles.
To find the number of moles of PCl3, you need to first calculate the number of moles of Cl atoms in 3.68 * 10^25 atoms. There are 3 Cl atoms in each molecule of PCl3, so you divide the number of Cl atoms by 3 to get the number of moles of PCl3.
4,37.10e-18 C atoms are equivalent to 7,25.10e-6 moles.