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One mole is 6.022 × 1023 (or 602,200,000,000,000,000,000,000) bits of anything. You have 18.9 moles. Thus:

18.9 × (6.022 × 1023) = 1.138158 × 1025 (or 11,381,580,000,000,000,000,000,000) molecules Cl2.

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How many atoms are in 189 g of calcium?

First, you need to figure out how many moles of calcium you have. One mole of calcium is 40.078g. So, divide 189g by 40.078. (189/40.078 = 4.716) Now, you can find out how many particles there are. There are 6.02*10^23 atoms in one mole. So, your answer will be 6.02*10^23 x 4.716 = 28.39 * 10^23.


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It is not easy to "explain a melting point" without having some context for the question or a compound to compare it to. What I can say is... 1. The melting point of hydrogen sulfide is -82 degrees C. 2. H2S is a polar molecule (has a similar shape to water) and so will have a higher melting point than similarly sized atoms or molecules that are not polar like argon (MP = -189 degrees C) or O2 (MP = -218 degrees C). 3. Lacking an O-H, F-H, or N-H bond, H2S cannot form hydrogen bonds with other H2S molecules, so it won't have as high a melting point as H2O (MP = 0 degrees C), even though H2O is a smaller molecule (weaker dispersion forces) and both are polar. 4. Even though H2S is polar it is relatively small, which means it will have only weak dispersion forces contributing to holding the molecules together. There are plenty of molecules out there like Br2 (MP = -7 degrees) that are non-polar but still have higher melting points. This is because they have big, polarizable electron clouds that make the dispersion forces that hold them together stronger than the combination of dipole-dipole and dispersion forces that hold H2S molecules together. So although I do not exactly think I have explained the melting point of hydrogen sulfide, hopefully I have given you enough context to show you why it has such a low (-82 degrees C) melting point.