How many moles of NCl3 contain 2.55x1024 chlorine atoms?

Answer 1

To find the number of moles of NCl₃ containing 2.55 x 10²⁴ chlorine atoms, we first note that each molecule of NCl₃ contains 3 chlorine atoms. Therefore, the number of NCl₃ molecules can be calculated by dividing the number of chlorine atoms by 3:

[ \frac{2.55 \times 10^{24}}{3} = 8.50 \times 10^{23} \text{ molecules of NCl}_3. ]

Next, to convert molecules to moles, we use Avogadro's number (6.022 x 10²³ molecules/mol):

[ \frac{8.50 \times 10^{23}}{6.022 \times 10^{23}} \approx 1.41 \text{ moles of NCl}_3. ]

Thus, there are approximately 1.41 moles of NCl₃ in 2.55 x 10²⁴ chlorine atoms.