The needed mass is 0,0584 g.
600 mL of 0,9 % sodium chloride: 6 x 0,9 = 5,4 grams NaCl
Balanced equation first. 2Na + Cl2 -> 2NaCl 35 grams NaCl (1 mole NaCl/58.44 grams )( 1 mole Cl2/2 mole NaCl )( 70.9 grams Cl2/1 mole Cl2) = 21 grams of Cl2 needed
It will be 11.5 gm od Na metal
The sodium chloride mass needed is 292,2 g
The needed mass of sodium chloride is 29,22 g.
Natrium is the latin name for sodium. Natrium chloride is salt. Measure 3 grams of salt, dissolve into 97 grams of water.
Sodium sulfate is not prepared from hydrogen chloride.
As the molar mass of sodium chloride is 58.5 g/mol, there are 175.5 grams in 3 moles.
23.3772 grams are there in four tenths moles of sodium chloride
You need 145,337 g silver nitrate.
The answer is 200 g sodium chloride.
It depends on the concentration of sodium chloride.
Coke doesn't contain sodium chloride.
In this instance, 50 mol of sodium chloride is needed and molar mass of NaCl is 58.5 g/mol. Hence the mass we need is 29250 g. But this amount of salt could not be dissolved in 500 ml of water, so we cannot prepare this solution practically.
Sodium chloride is the solute and water is the solvent.
0.40 moles NaCl (58.44 grams/1 mole NaCl) = 23 grams sodium chloride =================
molecular formula for sodium chloride = NaClIf the mole (n) for NaCl = 5.3 moles, then the mole of sodium (Na) = 5.3 moles as well. 1 to 1 ratio mass = moles X molar mass m = 5.3 x 22.9 = 121.37 grams of sodium in 5.3 moles of sodium chloride
The molecular mass of sodium chloride is approx. 58,44 g.