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Argon has a molar mass of about 40.

At STP 1 mole of argon would occupy 22.4 L. First find the number of moles, thne convert to mass.

(PV/nT)a = (PV/nT)b ... now substitute

(0.322 x 10.0)/(n x 298) = (1 x 22.4)/(1 x 273) ... solve for n

n = (1 x 22.4)/(1 x 273) x (298) / (0.322 x 10.0)

n = 7.59 moles

multiply by the molar mass to convert to grams.

7.59 x 40 = 303.6 grams

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Q: How many grams of Argon are in the container if it exerts a pressure of 0.322 ATM at 25C in a 10.0L container?
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