Want this question answered?
Two moles of water are produced.
First you need to find the balanced reaction:2S + 3O2 --> 2SO3So using the balanced reaction we see that for every 3 moles of oxygen consumed, 2 moles of sulfur trioxide are produced:1.2 moles O2 consumed * (2 moles SO3/3 moles O2) = 0.8 mole of SO3 produced
The answer is 165,5 g water.
5.0 grams CO2 (1mol CO2/44.01g) = 0.11 moles CO2
16 grams of oxygen how many moles is 0,5 moles.
323.2 grams of KO2 is equal to 4.55 moles of KO2. Per the equation, 3.4125 moles of O2 is produced which is equal to 2.055 E24 molecules of oxygen. This means that every mg of KO2 produces 6.36 E18 molecules of O2.
Two moles of water are produced.
First you need to find the balanced reaction:2S + 3O2 --> 2SO3So using the balanced reaction we see that for every 3 moles of oxygen consumed, 2 moles of sulfur trioxide are produced:1.2 moles O2 consumed * (2 moles SO3/3 moles O2) = 0.8 mole of SO3 produced
If 15 liters of propane are completely consumed 90,25 grams of carbon dioxide are produced.
33 grams aluminum (1 mole Al/26.98 grams) = 1.2 moles of aluminum ================
0,028 moles carbonic are obtained.
No moles of oxygen are produced by complete combustion of propane. Oxygen is CONSUMED, not produced. For combustion of 4 moles of propane, it will use 20 moles of oxygen.
The answer is 165,5 g water.
it will consume my dick
If the reaction were 2AlCl3 + 3Pb ---> 3PbCl2 + 2Al, then from this balanced equation, 14 moles of AlCl3 would produce 3/2 x 14 moles of PbCl2 = 21 moles of PbCl2.
The mass of ammonia will be 95,03 g.
5.0 grams CO2 (1mol CO2/44.01g) = 0.11 moles CO2