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How many grams of gaseous butane combust when 1550 kJ of heat are produced?
Wiki User
∙ 13y ago
1550 kj @ 1 mol / 2658 kJ = 0.5831 moles of butane
Wiki User
∙ 13y ago
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How many grams of carbon dioxide would be produced by the complete combustion of 600 g of butane?
The chemical reaction of burning is: 2C4H10 + 13O2 = 8CO2 + 10H2O From 600 g butane, after a complete combustion, 1817,34 g carbon dioxide are released.
How many grams of oxygen are needed for the complete combustion of the butane in the lighter?
The variables for the formula are incomplete. You would need to know how many grams of butane are put out by the lighter. The molecular weight of butane is 58.12 g/mol, which is also needed to complete the formula.
What is the mass of water vapor formed when 1g of butane is burned in a lighter?
Balanced equation. 2C4H10 + 13O2 -> 8CO2 +10H2O 8.13 grams C4H10 (1 mole C4H10/58.12 grams)(10 moles H2O/2 mole C4H10)(18.016 grams/1 mole H2O) = 12.6 grams water produced
How many grams is 300 ml of butane?
170 to 190 grams depending on pressure. ie sea level or higher...
How many grams of CO2 is produced in the combustion of 100g butane?
C4H10 + 6.5 O2 -----> 4CO2 + 5H20 Mr of Butane = 58 5.8/58 = 0.1 So there is 0.1 moles of butane reacting 1 Mole = 24dm3 so 0.1 moles (5.8g of butane) = 0.1x24(dm3) = 2.4dm3 So then you see in the equation 4 moles of CO2 to 1 mole of C4H10 Thus 2.4 x 4 = Volume of CO2 = 9.6dm3 I think this is right, correct if wrong.
How many grams of carbon dioxide would be produced by the complete combustion of 600 g of butane?
The chemical reaction of burning is: 2C4H10 + 13O2 = 8CO2 + 10H2O From 600 g butane, after a complete combustion, 1817,34 g carbon dioxide are released.
How do you find the number of moles that will react with 5 grams of butane?
We need to know the number of moles of WHAT is to react with the butane to provide you with an answer.
How many grams of oxygen are needed for the complete combustion of the butane in the lighter?
The variables for the formula are incomplete. You would need to know how many grams of butane are put out by the lighter. The molecular weight of butane is 58.12 g/mol, which is also needed to complete the formula.
How many grams of water are formed when 5.00g of butanol combust with excess oxygen?
6.08
What is the mass of water vapor formed when 1g of butane is burned in a lighter?
Balanced equation. 2C4H10 + 13O2 -> 8CO2 +10H2O 8.13 grams C4H10 (1 mole C4H10/58.12 grams)(10 moles H2O/2 mole C4H10)(18.016 grams/1 mole H2O) = 12.6 grams water produced
How many grams is 300 ml of butane?
170 to 190 grams depending on pressure. ie sea level or higher...
How many grams of CO2 is produced in the combustion of 100g butane?
C4H10 + 6.5 O2 -----> 4CO2 + 5H20 Mr of Butane = 58 5.8/58 = 0.1 So there is 0.1 moles of butane reacting 1 Mole = 24dm3 so 0.1 moles (5.8g of butane) = 0.1x24(dm3) = 2.4dm3 So then you see in the equation 4 moles of CO2 to 1 mole of C4H10 Thus 2.4 x 4 = Volume of CO2 = 9.6dm3 I think this is right, correct if wrong.
How many grams of H 2O will be produced if 750 grams of Fe are produced?
322 grams.
How many grams of NaCL are produced when 80.0 grams of O2 are produced?
96.75 grams of NaCl
How many moles of co2 form when 58 grams of butane burn in oxygen?
The answer is 3,99 moles of carbon dioxide.
What is the molar mass of butanal?
The Molar mass of Butane / C4H10 = 58.1222 g/mol
How many moles of CO2 form when 58 grams of butane C4H10 burn in oxygen?
The answer is 3,99 moles of carbon dioxide.
