The rusting of iron has the reaction 4 Fe + 3 O2 equals 2 Fe2O3. So every 2 moles of iron produces 1 moles of iron oxide. 16.7 grams is .299 moles of iron. This means there are 0.149 moles of iron oxide or 23.88 grams.
Tell you what - the more likely scenario is that iron reacts with oxygen to form 6.2g of Fe2O3. That's the rusting of iron; I don't know if you can "un-rust" iron back into pure iron and oxygen. So we'll go with this equation:
4Fe + 3O2 --> 2Fe2O3.
Iron (Fe) is our unknown. Okay, Fe2O3, which is iron(III) oxide, has a given mass of 6.2g, and according to the Periodic Table, it's molar mass, or grams per 1 mole, is 160g/mol (56+56+16+16+16). Do a 1-step molar conversion to get about 0.03875 moles. Apply this to the molar ratio of coefficients in the balanced equation: the ratio is 2:4, or 1:2, so you will double that to 0.0775 moles of iron. Now do a 1-step molar conversion with iron's Atomic Mass to get your grams of iron: 0.0775 moles x 56 grams per mole = 4.34 grams Fe.
32,22 g of Fe2O3
23.9
23.95g
When iron reactions with oxygen to form rust, the iron atoms, Fe reacts with the oxygen atoms, O2 to create iron (III) oxide, Fe2O3.4Fe + 3O2 -----> 2Fe2O3Or2Fe + 3/2O2 -----> Fe2O3
If an iron nail is exposed to air for a long time it reacts with the water vapour (moisture) and oxygen present in the atmosphere and a reddish-brown powdery coating is formed on it known as RUST (Fe2O3.xH2O) .
Fe2O3 contains the elements Iron and Oxygen. It would have 2 Iron and 3 oxygen.
The oxide Fe2O3 has 3 oxygen atoms in the molecule.
23.95g
Fe2O3 It is neither an acid or a base, and it is a compound, not an element
Iron reacts with oxygen to form Fe2O3 also known as rust. Oxygen requires two electrons to fill it's valence shell so iron loses electrons.
Pyrite (fools gold) reacts with Oxygen to make Hematite (Fe2O3) and Sulpher dioxide (SO2) The reaction is oxidation of pyrite. 2FeS2 + 3.5O2 - - Fe2O3 + 2SO2
When iron reactions with oxygen to form rust, the iron atoms, Fe reacts with the oxygen atoms, O2 to create iron (III) oxide, Fe2O3.4Fe + 3O2 -----> 2Fe2O3Or2Fe + 3/2O2 -----> Fe2O3
If an iron nail is exposed to air for a long time it reacts with the water vapour (moisture) and oxygen present in the atmosphere and a reddish-brown powdery coating is formed on it known as RUST (Fe2O3.xH2O) .
Fe2O3 contains the elements Iron and Oxygen. It would have 2 Iron and 3 oxygen.
The oxide Fe2O3 has 3 oxygen atoms in the molecule.
Iron does not react with pure water. Dissolved oxygen reacts with iron. Rust is a complex mixture of iron oxides, and hydroxide and hydrated oxides. See the link for a reasonably detailed explanation.
in one molecule of Fe2O3 there would be 3 oxygen atoms
The chemical equation is:4 Fe + 3 O2 = 2 Fe2O3
Iron reacting with oxygen produces rust, Fe2O3 (Iron (III) oxide) or FeO2 (Iron (II) oxide) depending on the composition of the iron.