sorry, this page does not contain answer, for more information go to Chemistry homework website
You need 1,675 g KOH.
2.41 grams
160 g (solution) - [5/100*160] g (solute) = 152 g (solvent) water
From the definition of molar concentration, the required amount of solute for the solution specified is 0.125 moles. The gram formula mass for potassium benzoate trihydrate is 214.26. Therefore, the mass required is 0.125 X 214.26 or about 26.8 grams, to the justified number of significant digits.
7.5 grams are needed because each milliliter is 1.50 grams, to get 5.00 mls, the calculation would be 5x1.50=7.5.
(1.550M/liter of solution)(122.55 g/mole of KCLO3) = 190.0 g/liter(190.0 g/ 1000 mL) x 250.0 mL = 47.50 g/250.0 mL
200 grams of solution will contain 200 x 4% or 200 x 0.04 = 8.0 total grams of solute.
More than 45,5 g KNO3.
290 grams
530,3 g potassium iodide are needed.
160 g (solution) - [5/100*160] g (solute) = 152 g (solvent) water
50 grams
From the definition of molar concentration, the required amount of solute for the solution specified is 0.125 moles. The gram formula mass for potassium benzoate trihydrate is 214.26. Therefore, the mass required is 0.125 X 214.26 or about 26.8 grams, to the justified number of significant digits.
Potassium oxide violently react with water !
7.5 grams are needed because each milliliter is 1.50 grams, to get 5.00 mls, the calculation would be 5x1.50=7.5.
(1.550M/liter of solution)(122.55 g/mole of KCLO3) = 190.0 g/liter(190.0 g/ 1000 mL) x 250.0 mL = 47.50 g/250.0 mL
200 grams of solution will contain 200 x 4% or 200 x 0.04 = 8.0 total grams of solute.
HCl has a molar mass of 36.461 grams per mole. This means that 72.922 grams of HCl are needed per liter of water to make a solution that has a concentration of 2M.
Calculate the mass (in grams) of sodium sulfide that is needed to make 360ml of a 0.50 mol/L solution