HomeHow many grams of KOH are needed to make 250.0 mL of a solution that is to contain 6.70 mgmL of potassium ion?
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More than 91 grams of potassium nitrate for 100 mL water.
530,3 g potassium iodide are needed.
160 g (solution) - [5/100*160] g (solute) = 152 g (solvent) water
an unsaturated solution of NH4Cl
From the definition of molar concentration, the required amount of solute for the solution specified is 0.125 moles. The gram formula mass for potassium benzoate trihydrate is 214.26. Therefore, the mass required is 0.125 X 214.26 or about 26.8 grams, to the justified number of significant digits.
7.5 grams are needed because each milliliter is 1.50 grams, to get 5.00 mls, the calculation would be 5x1.50=7.5.
200 grams of solution will contain 200 x 4% or 200 x 0.04 = 8.0 total grams of solute.
Potassium oxide violently react with water !
HCl has a molar mass of 36.461 grams per mole. This means that 72.922 grams of HCl are needed per liter of water to make a solution that has a concentration of 2M.
This is not a possible compound. Please state the chemical name of this Potassium-Hydrogen salt of 'WHAT" accurately.
how many grams of calcium nitrate are needed to make a 500ml volume of a .5 molar solution
This solution contain 26,3 g NaOH.
(1.550M/liter of solution)(122.55 g/mole of KCLO3) = 190.0 g/liter(190.0 g/ 1000 mL) x 250.0 mL = 47.50 g/250.0 mL
The cost of potassium is: Bulk Potassium: $65 per 100 grams Pure Potassium: $100 per 100 grams
The cost of potassium is: Bulk Potassium: $65 per 100 grams Pure Potassium: $100 per 100 grams
Molarity = moles of solute/Liters of solution ( 100 mL = 0.1 Liters)Moles of solute (K2SO4) = Liters of solution * MolarityMoles K2SO4 = 0.1 Liters * 0.1 M= 0.01 moles K2SO4 (174.27 grams/1 mole K2SO4)= 1.7 grams potassium sulfate=======================Add that many grams potassium sulfate to your 100 mL.
The solution contain 12,47 g KI.
The answer is 7,5g.
The solution become saturated ove 124,6 g potassium nitrate.
This solution contain 2,89 g sulfuric acid.
50.0mL of a 1.50 M solution of H3PO4 contain 7,35 g acid.
What is the mass, in grams, of 2 × 1012 atoms of potassium?
Molarity = moles of solute/Liters of solution some conversion needed 5.00 X 102 ml = 0.5 liters ------------------------------------- 249 grams K (1 mole K/39.10 grams = 6.37 moles potassium ------------------------------------------------------------------------------- Molarity = 6.37 mole K/0.5 Liters = 12.7 M K -----------------( as expected, highly concentrated solution )
I suppose that this solution doesn't exist.
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