There are 0.003659 N2O moles. So there are o.007318 moles of N.
3.18 mol 70.0gN2O x 1mol N2O/44.013g x 2mol N/1mol N2O
For this you need the atomic (molecular) mass of NaNO3. Take the number of grams and divide it by the atomic mass. Multiply by one mole for units to cancel. NaNO3=85.0 grams60.1 grams NaNO3 / (85.0 grams) = .707 moles NaNO3
0.6 ounces is 17.01 grams.
10 grams nitrogen (1 mole N/14.01 grams)(6.022 X 1023/1 mole N) = 4.3 X 1023 atoms of nitrogen ======================
There are 0.003659 N2O moles. So there are o.007318 moles of N.
0,189 g of N2O equal 0,0043 mol.
The number of moles is 3,316 (for atomic nitrogen).
[ 217(g) / 44.013(g/mol) ] * 2(molN/molN2O) = 9.86 mol NDivide mass (g) by molar mass (g/mol) to get moles of N2O, this should be multiplied by 2 for the stoechiometric factor of atoms N per molecule N2O.
Molar mass: 44.013 g/mole 81.0/44.013=1.84 mole N2O Moles of N 1 mole N2O contains 2 atoms N 1.84 mole N2O contain 1.84*2=3.68 mole N atoms
3.18 mol 70.0gN2O x 1mol N2O/44.013g x 2mol N/1mol N2O
When using the preferred resonance structure [ N (triple bond) N (single bond) O ] the bond order of N-O in N2O is 1.
The answer is 1,52 moles.
One molecule of N2O N 2 O contains one atom of oxygen.
This is a thermal decomposition reaction.
For this you need the atomic (molecular) mass of NaNO3. Take the number of grams and divide it by the atomic mass. Multiply by one mole for units to cancel. NaNO3=85.0 grams60.1 grams NaNO3 / (85.0 grams) = .707 moles NaNO3
- .. SP linear geometry :N=N-o: ..