how many grams of calcium nitrate are needed to make a 500ml volume of a .5 molar solution

HCl has a molar mass of 36.461 grams per mole. This means that 72.922 grams of HCl are needed per liter of water to make a solution that has a concentration of 2M.

I suppose that this solution doesn't exist.

Only a compound has a molar mass not a solution.

To convert to per litre we multiply weight by 2. This gives 40 grams per litre. 40g divided by 40g/mol is a 1 molar solution.

100mL is needed to neutralize 50 ml of a 0.2 molar solution of HCL.

FeS + 2HCl >> FeCl2 + H2S 75 grams FeS (1mole FeS/87.92 grams)(2 mole HCl/1 mole FeS) = 1.71 moles HCl 2 Molar HCl = 1.71 moles HCl/Liters = 0.855 Liters HCl, or as asked for; 855 milliliters of hydrochloric acid needed

A 0.205 M solution will have 0.205 moles per liter. 250 milliliters is 1/4 of a liter, so in that sample, there will be 0.05125 moles. NaOH has a molar mass of 39.9971 grams per mole, so 2.05 grams added to 250 mL of water will make the desired solution.

Calcium sulfate is very low soluble in water - 2,1 g/L at 20 0C.

Molarity = moles of solute/Liters of solution 3 M KBr = moles KBr/1 liter = 3 moles KBr (119 grams/1 mole KBr) = 357 grams needed

H2SO4 has a molar mass of 98.1 grams per mole. To prepare a 0.5 M solution, add 49.05 grams of sulfuric acid per liter of water.

Molarity = moles of solute/volume of solution 1.50 M = X Moles/125ml = 187.5 millimoles, which is 0.1875 moles The molar mass of CaCl2 = 110.98 grams 0.1875 moles CaCl2 (110.98g/1mol) = 20.8 grams needed

~58.5 g ~58.5 g 58.443 g

It is necessary to know the molar mass of the solute to answer.

342 grams of Lactose in 1 litre water or 34.2 grams in 100 mls.

The molar concentration of the hydrogen ions

The answer is 830,014 grams.

In 500ml there are 3.5 grams. Therefore in 1 litre, there are 7g. 7/58.443 is 0.1198 molar.

Take twice its molar mass in grams and then dissolve in water up to 1.000 Litre

The molar solution of NaCl has 58.44 g in 1 L water.

The molar concentration is 2.91 M of ammonia.

Approximately eighty-nine grams of KO2 are needed to prepare 100 grams of O2. This chemical equation is a prime example of how to determine the amount needed based on the molar mass.

convert to liters, then multiply by density of substance. with the grams, use the moles=mass/molar mass to find moles

There is 0.5 moles of NaOH per litre To calculate 0.5 molar NaOH first know the molecular weight of NaOH i.e 40 now multiply the number of moles of NaOH you have (0.5) found as above. so to find the number of grams of NaOH we needed to start with (0.5) * (40) = 20g So dissolve 20g of NaOH in one litre of the solution to prepare 0.5 molar solution

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